Question

The equation of straight line passing through the point (1,2) and parallel to the line y = 3x + 1 is (a) y = 3x - 1 (b) y = -3x +1 (c) y = -3x - 1 (d) y = 3x + 1​

Answer 1

Answer:

the answer is y=-3x+5

since it's parallel, the slope is the same. so m=-3

use point slope formula y-y1=m(x-x1) and plug in the slope and the point

y-2=-3(x-1)

y-2=-3x+3

y=-3x+5