The equation of straight line passing through the point (1,2) and parallel to the line y = 3x + 1 is (a) y = 3x - 1 (b) y = -3x
+1 (c) y = -3x - 1 (d) y = 3x + 1
1 answer:
Answer:
the answer is y=-3x+5
since it's parallel, the slope is the same. so m=-3
use point slope formula y-y1=m(x-x1) and plug in the slope and the point
y-2=-3(x-1)
y-2=-3x+3
y=-3x+5
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