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Neko [114]
3 years ago
8

The equation of straight line passing through the point (1,2) and parallel to the line y = 3x + 1 is (a) y = 3x - 1 (b) y = -3x

+1 (c) y = -3x - 1 (d) y = 3x + 1​
Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

the answer is y=-3x+5

since it's parallel, the slope is the same. so m=-3

use point slope formula y-y1=m(x-x1) and plug in the slope and the point

y-2=-3(x-1)

y-2=-3x+3

y=-3x+5

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