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Reika [66]
2 years ago
12

In printing an article of 48,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contai

ns 1,800 words. Using smaller type, a page contains 2,400 words. The article is allotted 21 full pages in a magazine. How many pages must be in smaller type
Mathematics
1 answer:
9966 [12]2 years ago
7 0

Answer:

17 pages

Step-by-step explanation:

Let L = number of pages printed Larger type

S = number of pages printed smaller type

 the article is allow 21 full pages in a magazine. -->L + S = 21

1,800L + 2, 400S = 48, 000 (we can divide 100 to make the math easier)

18L + 24S = 480

Solve:

L + S = 21

18L + 24S = 480

we can use elimination by eliminating 18L so we can isolate the value of S  

-18 (L + S = 21)

18L + 24S = 480

-18L - 18S = 378

18L + 24S = 480

6S = 102

S = 17

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3 years ago
How do you write the logarithmic equation in exponential form when you use ln?
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E^0.693 = 1/2       ln = log e
5 0
2 years ago
Given: is an angle bisector of ∠JMK<br><br><br>Prove: m
astraxan [27]

Answer:

An angle bisector is a line passing through the vertex of the angle that cuts the angle into two equal smaller angles.

Given: MN is angle bisector,

then  

\angle JMN \cong \angle NMK            .......  [1]

Congruent angles are  two or more angles that have the same measure.

then;

by definition of congruent angles

[1]⇒ m\angle JMN = m\angle NMK                ......[2]

By the  Angle addition postulates states that if M is in the interior of ∠JMK then,

m\angle JMN+m\angle NMK =m\angle JMK            ......[3]

Now, by substitution property ; substitute the equation [2] in [3] we get;

m\angle JMN+m\angle JMN =m\angle JMK                 ......[4]

Like terms terms whose variables  are the same

Combine like terms in equation [4] we get

2 \cdot m\angle JMN=m\angle JMK                      ......[5]

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 2 to both sides in equation [5] , we get

m\angle JMN= \frac{1}{2} m\angle JMK    


5 0
3 years ago
Find two integers whose sum is -20 and product is 99
Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

-11+y=-20

y=-20=11=-9

when x=-9

-9+y=-20

y=-20+9=-11

so integers  are -11,-9

8 0
2 years ago
Read 2 more answers
Evaluate this expression. 5^-3
sweet-ann [11.9K]

Answer:

\Huge \boxed{\frac{1}{125}}

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

\displaystyle \frac{1}{5^3}

\displaystyle 5^3=5\times5\times5=125

\displaystyle \frac{1}{125}=125

\large \boxed{\frac{1}{125}}, which is our answer.

Hope this helps!

4 0
3 years ago
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