What is the value of x?

Mathematics

1 answer:

fiasKO [112]3 years ago

4 0

All 3 angles are the same which means all 3 sides are also the same.

Pick any 2 sides, set them equal to each other and solve for x

5x-22 = 4x -10

Add 22 to both sides

5x = 4x + 12

Subtract 4x from both sides

X = 12

You might be interested in

Find the value of the variable y in the equation –5.7 + y = 8.2.

emmasim [6.3K]

Answer:

y = 13.9

Step-by-step explanation:

It is given that

–5.7 + y = 8.2. -----(1)

Equation (1) is a linear equation in one variable.

LHS consists of a constant and a variable term

RHS consists of only constant term

<u>Find the value of y</u>

Solving the equation

-5.7 + y = 8.2

moving -5.7 to the RHS

y = 8.2 + 5.7

y = 13.9

Therefore the value of y = 13.9

-5.7 + y = 8.2

5 0

3 years ago

Mr. Parks took his grandchildren to a baseball game with plans to spend no more than $35 on snacks. An order of nachos costs $5

Nataly [62]

I think the right answer is b i'm not sure

3 0

3 years ago

Write the quadratic function in vertex form.

melisa1 [442]

Complete the square
isolate x terms
y=(x^2-14x)+53
take 1/2 of -14 and square it ((-7)^2=49
add plus and minus of that inside the parntehasees

y=(x^2-14x+49-49)+53
factor perfect suqrae
y=((x-7)^2-49)+53
get rid of parnthasees
y=(x-7)^2-49+53
y=(x-7)^2+4

C isi answer

6 0

4 years ago

Archimedes calculated the volume of a sphere by comparing it to what solid? prism cylinder pyramid box

Stella [2.4K]

<h2>Answer:</h2>

cylinder

<h2>Step-by-step explanation:</h2>

Archimedes was a brilliant mathematician. This man rose the formula of the volume of a sphere by comparing this shape to a cylinder. The volume of a sphere is hard to calculate by comparing this object to a cube. So Archimedes imagined cutting a sphere into two halves, called hemispheres. So an hemisphere gave him a flat surface, which is easier to work with. Therefore, if he'd find the volume of a hemisphere, then he'd multiply the result by 2 and would get the volume of a sphere. Then he imagined a hemisphere within a cylinder as the one shown below. Also, he imagined a cone within the same cylinder. <em>What did he find? </em>He found that the volume of the hemisphere should be equal to the volume of the cylinder minus the volume of the cone:

$V=\pi r^3-\frac{1}{3}\pi r^3 \\ \\ V=\frac{2}{3} \pi r^3$