Answer:
Step-by-step explanation:
1) 2x -y = 1 -------1
3x - y = -6 ------2
Subtract eqn 2 from eqn 1
-x = 1--6 = 7
x = -7
Put x= -7 in eqn 1
2*-7-y = 1
-14-y = 1
- y = 15
y = -15
2) 4x +2y = 10------1
y = 4x + 2--------2
Put eqn 2 in eqn 1
4x + 2 ( 4x+ 2) = 10
4x + 8x + 4 = 10
12x = 6
x = 6/12 = 1/2
Put x = 1/2 in eqn 2
y = 4* 1/2 + 2= 2 + 2
= 4
3) 6x - y = 2------1
y = 3x + 4---------2
Put eqn 2 in eqn 1
6x - (3x +4) = 2
6x - 3x - 4 = 2
3x = 6
x = 2
y = 3*2 + 4 = 6 + 4
= 10
Hey I'm in 6th too, Simplify means to solve the prob
Subtract 3 both sides first. R-3=ts²
next, divide both sides by t, (R-3)/t=s²
finally, take the square root of both sides
√(R-3)/t = s. 2nd choice.
Circle = (x-h)^2 + (y-k)^2 = r^2
Center is (h,k) h = -5, k = 2
Radius is 4, r = 4
(x - -5)^2 + (y - 2)^2 = 4^2
(x + 5)^2 + (y - 2)^2 = 16
Answer:
Sue // 6 More blocks
Step-by-step explanation:
Sue has more blocks because 34>28.
34-28 is 6 so sue has 6 more.
