Question

ammonium bromide reacts with copper(i) sulfate in aqueous solution to form a solid precipitate. what is the net ionic equation for this reaction

Answer 1

Answer:

$Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)$

Explanation:

Hello,

In this case, the molecular chemical reaction is written as:

$2NH_4Br(aq)+Cu_2S(aq)\rightarrow 2CuBr(s)+(NH_4)_2SO_4(aq)$

In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:

$2NH_4^+(aq)+Br^-(aq)+Cu^+(aq)+SO_4^{2-}(aq)\rightarrow CuBr(s)+NH_4^+(aq)+SO_4^{2-}(aq)$

Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:

$Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)$

Regards.