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Rudiy27
3 years ago
12

Distance from shore (in cm) Depth

Chemistry
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

Its 25

Explanation:

Njnnnc

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Perform an on-line search to discover what conditions are favourable to the growth of moss. be sure to include a comment on ph c
Genrish500 [490]
Moss can grow abundantly in an environment with favorable conditions. They usually grow abundantly in cool, moist and dark places. If not dark, they prefer shady areas. Also, they tend to grow in acidic soil with pH range between 5.0-5.5. 
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4 years ago
When a skin diver is on the top of the water at 1.03 atm, her lung volume is 3.62L. How will the volume of her lungs change as s
Anon25 [30]

Answer:

–2.23 L

Explanation:

We'll begin by calculating the final volume. This can be obtained as follow:

Initial pressure (P₁) = 1.03 atm

Initial volume (V₁) = 3.62 L

Final pressure (P₂) = 2.68 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

1.03 × 3.62 = 2.68 × V₂

3.7286 = 2.68 × V₂

Divide both side by 2.68

V₂ = 3.7286 / 2.68

V₂ = 1.39 L

Finally, we shall determine the change in volume. This can be obtained as follow:

Initial volume (V₁) = 3.62 L

Final volume (V₂) = 1.39 L

Change in volume (ΔV) =?

ΔV = V₂ – V₁

ΔV = 1.39 – 3.62

ΔV = –2.23 L

Thus, the change in the volume of her lung is –2.23 L.

NOTE: The negative sign indicate that the volume of her lung reduced as she goes below the surface!

3 0
3 years ago
if you are using a formula where you need the change in temperature, explain why it is not important whether your temperatures a
alexandr1967 [171]

Answer:

This is because, Kelvins and Celcius degrees both agree at fixed points i.e; the lower fixed point and upper

5 0
3 years ago
Nitrogen - 14.0067
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Answer:

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Explanation:

3 0
3 years ago
Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce
Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

3NO_{2} +H_{2}O -->2HNO_{3} +NO

Then we calculate the number of moles of nitric acid produced

n(HNO3) = \frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g

5 0
3 years ago
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