3 years ago

Which set of ordered pairs lies along the same vertical line?

Mathematics

1 answer:

Phantasy [73]3 years ago

3 0

Answer:

All ordered pairs with the same x value

Step-by-step explanation:

A vertical line can be represented by the equation x=k for some value k. So any pair with x value equal to k satisfies the equation and is thus in the set

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2(x+9)= [ ]x + [ ] what is the answer I’m struggling in math rb please help!!

Anarel [89]

Answer:

2x+18

Step-by-step explanation:

We can start by distributing the 2 to each term in the parentheses...

2(x)+2(9)

Multiply

2x+18

7 0

2 years ago

Read 2 more answers

What is 18 x 9.24 step by step?

Tanzania [10]

Answer: 166.32

Step-by-step explanation: multiply 18 by 9 first. (162) then multiply the decimal numbers. Then at that to the previous product.

7 0

3 years ago

Write a recursive rule for the sequence 4,10,16,22

Phantasy [73]

Answer:

$a_{n+1}$ = $a_{n}$ + 6

Step-by-step explanation:

The terms have a common difference d between consecutive terms, that is

10 - 4 = 16 - 10 = 22 - 16 = 6

To obtain the next term add 6 to the previous term ( recursive rule ), thus

$a_{n+1}$ = $a_{n}$ + 6 with a₁ = 4

8 0

3 years ago

Suppose $p(x)$ is a monic cubic polynomial with real coefficients such that $p(3-2i)=0$ and $p(0)=-52$. determine $p(x)$ (in exp

Maslowich

If $p(3-2i)=0,$ then complex number $3-2i$ is a root of cubic polynomial.

If polynomial has real coefficients, then conjugated $3+2i$ is also a root of polynomial.

Then the polynomial will be of a form

$p(x)=(x-(3-2i))(x-(3+2i))(x-a).$

Since $p(0)=-52,$ then

$-52=(0-(3-2i))(0-(3+2i))(0-a),\\ \\-52=(2i-3)(3+2i)a,\\ \\-52=(4i^2-9)a,\\ \\-52=(-4-9)a,\\ \\-13a=-52,\\ \\a=4.$

Therefore,

$p(x)=(x-(3-2i))(x-(3+2i))(x-4),\\ \\p(x)=(x^2-6x+13)(x-4),\\ \\p(x)=x^3-10x^2+37x-52.$

3 0

3 years ago

What is the product of 18 and 5 less than a number 162?

kondor19780726 [428]

5 less than 162=162-5
=157
Product=18x157
=2826

7 0

4 years ago