Complete Question
A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)
Answer:
The velocity is 
Explanation:
From the question we are told that
The magnitude of the electric field is 
The magnetic field is 
The force due to the electric field is mathematically represented as
and
The force due to the magnetic field is mathematically represented as
Now given that it is perpendicular , 
=> 
=> 
Now given that it is not deflected it means that
=> 
=> 
substituting values
An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
<h3>What is mechanical energy?</h3>
Mechanical energy is the sum of potential energy and kinetic energy.
Total mechanical energy = P.E max = K.E max
Total mechanical energy = K.E +P.E
Given is the kinetic energy is (3/4)E.
E= (3/4)E + P.E
P.E = (1/4) E
Maximum potential energy =E = (1/2) k A²
Here. A is the maximum displacement and k is the spring constant.
The potential energy at kinetic energy of (3/4) E is
P.E = (1/4)E = (1/8) k A²
Therefore, the system's potential energy when kinetic energy of (3/4) E is (1/8) k A².
Learn more about mechanical energy.
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Let's list the given information. The frictional force, denoted as Ff, is equal to 0.200 N. We have to find the normal force, denoted as Fn. The relationship between Ff and Fn is written as:
Ff = μFn
where μ is the coefficient of friction
If there is no given data for μ, we can't solve this problem. Suppose μ = 0.5, then the normal force would be:
Fn = Ff/μ = 0.2/0.5 = 0.4 N
Answer:
Explanation:
Given
mass of chair m=21 kg
Force required to set chair in motion is 175 N
Once the chair is in motion 137 N is require to move it with constant velocity
i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force
thus
where 
is the coefficient of static friction and N is Normal reaction
Answer:
a) 17.086m
b) 0.1671 m
Explanation:
Given data: speed of water through the hose = 1.81 m/s
through the nozzle = 18.3 m/s
We know that maximum height of an object with upward velocity v is given by,
a) H = v^2/2g
where H is the maximum height water emerges
= 18.3^2/(2×9.8) = 17.086 m answer
b) Again,
H = v^2/2g
= 1.81^2/(2×9.8) = 0.1671 m
