Answer:
Making of an ice cube. Making ice cube is a process of liquid changing its state to solid. ...
Snow formation in clouds. ...
Burning of a candle. ...
Rusting of iron. ...
Burning of sugar. ...
Formation of ion pairs. ...
Reaction of Strong acid and Water. ...
Water and calcium chloride.
Explanation:
Answer:
Explanation:
The options is not well presented
This are the options
A. θ = at³ + b
B. θ = at² + bt + c
C. θ = at² — b
D. θ = Sin(at)
So, we want to prove which of the following option have a constant angular acceleration I.e. does not depend on time
Now,
Angular acceleration can be determine using.
α = d²θ / dt²
α = θ''(t)
So, second deferential of each θ(t) will give the angular acceleration
A. θ = at³ + b
dθ/dt = 3at² + 0 = 3at²
d²θ/dt² = 6at
α = d²θ/dt² = 6at
The angular acceleration here still depend on time
B. θ = at² + bt + c
dθ/dt = 2at + b + 0 = 2at + b
d²θ/dt² = 2a + 0 = 2a
α = d²θ/dt² = 2a
Then, the angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
C. θ = at² —b
dθ/dt = 2at — 0 = 2at
d²θ/dt² = 2a
α = d²θ/dt² = 2a
Same as above in B. The angular acceleration here is constant is "a" is a constant and the angular acceleration is independent on time.
D. θ = Sin(at)
dθ/dt = aCos(at)
d²θ/dt² = —a²Sin(at) = —a²θ
α = d²θ/dt² = -a²θ
Since θ is not a constant, then, the angular acceleration is dependent on time and angular displacement
So,
The answer is B and C
Answer:
The force between the Earth and the object is, F = 9.61 x 10⁻¹² N
Explanation:
Given data,
The mass of the Earth, M = 5.9 x 10²⁴ kg
The mass of the object, m = 10 kg
The gravitational force between the earth and the object is given by the formula,
F = G Mm/R²
Substituting the given values in the above equation,
F = 6.673 x 10⁻¹¹ x 5.9 x 10²⁴ x 10 / 6.4 x 10⁶
= 9.61 x 10⁻¹² N
Hence, the force between the Earth and the object is, F = 9.61 x 10⁻¹² N
Well, i would tell the kid that light is electromagnetic radiation which
is visible. The frequency and wavelength is just right so the radiation
becomes visible, and that visible radiation goes away from the star and
reaches earth
It also depends on the age of the child and the comprehension level