<u>Answer:</u> The amount of heat released when 0.211 moles of 
reacts is 554.8 kJ
<u>Explanation:</u>
The chemical equation for the reaction of 
with oxygen gas follows:
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%285%5Ctimes%20%5CDelta%20H_f_%7B%28B_2O_3%28s%29%29%7D%29%2B%289%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%28l%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28B_5H_9%28l%29%29%7D%29%2B%2812%5Ctimes%20%5CDelta%20H_f_%7B%28O_2%28g%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%282%5Ctimes%20%28-1272%29%29%2B%289%5Ctimes%20%28-285.4%29%29%5D-%5B%282%5Ctimes%20%2873.2%29%29%2B%2812%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D-5259kJ)
To calculate the amount of heat released for the given amount of , we use unitary method, we get:
When 2 moles of reacts, the amount of heat released is 5259 kJ
So, when 0.211 moles of will react, the amount of heat released will be = 
Hence, the amount of heat released when 0.211 moles of reacts is 554.8 kJ
Explanation:
Acidic pH can be between 0 and 6. Hence the answer is D.
7 is neutral whereas 10 and 14 are basic.
The new temperature : 11.56 °C
<h3>Further explanation </h3>
Boyle's law and Gay Lussac's law
P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = final gas pressure
V2 = final gas volume
T1 = initial gas temperature (K)
T2 = final gas temperature
V₁=4.39 L
T₁=44+273=317 K
P₁ = 729 torr = 0,959211 atm
V₂=3.78 L
P₂= 1 atm
The known constant of water is that it freezes at 0 degrees Celsius and boils at 100 degrees Celsius. it can be determined that because of the solute added the water becomes a compound meaning it no longer has the constants of pure water hence the difference in freezing point
Answer:
Explanation:
Given
Required
Determine the area
The area of a triangle is :
By substituting values for the x and y coordinates of A, B and C;
We have:
So:
For instance
The area is:
