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aleksandr82 [10.1K]
3 years ago
10

Which principle of the software engineering code of ethics has gilbert violated?.

Engineering
1 answer:
Yuki888 [10]3 years ago
7 0

Answer:

Judgement

Explanation:

Gilbert is required by the Judgement Principle to "disclose those conflicts of interest that cannot reasonably be avoided or escaped." Since Gilbert professionally believes that the software meets specifications, secures documents, and satisfies user requirements, it is not clear if he violated any principle. However, he could have informed his client of his interest in the software and also presented other software packages of different companies from which the client could make its independent choice.

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Electrical circuits must be locked-out/tagged-out before electricians work on any equipment. Is this true or false?
dybincka [34]

Answer:

true

Explanation:

Equipment that are "locked-out/tagged-out" <em>prevent the electrician from being electrocuted</em> or attaining a serious injury in relation to it. Locking out an equipment prevents it from releasing its energy because such energy can be <em>hazardous</em> to the electrician. There are instances when the equipment accidentally starts up, thus, it is essential that the equipment's source of energy is<em> isolated.</em>

8 0
3 years ago
3) What kind of bridges direct their load along it's curve and into the
AlladinOne [14]

Explanation:

suspension is the answer

8 0
3 years ago
A composite wall is composed of 20 cm of concrete block with k = 0.5 W/m-K and 5 cm of foam insulation with k = 0.03 W/m-K. The
wariber [46]

Answer:

4.8°C

Explanation:

The rate of heat transfer through the wall is given by:

q=\frac{Ak}{L}dT

\frac{q}{A}=\frac{k}{L}dT

Assumptions:

1) the system is at equilibrium

2) the heat transfer from foam side to interface and interface to block side is equal. There is no heat retention at any point

3) the external surface of the wall (concrete block side) is large enough that all heat is dissipated and there is no increase in temperature of the air on that side

{k_{fi}= 0.03 W/m.K

{L_{fi}= 5 cm = 0.05 m

{T_{fi}= 25 \°C

{k_{cb} = 0.5 W/m.K

{L_{cb}= 20 cm = 0.20 m

{T_{cb}= 0 \°C

{T_{m}= ? \°C = temperature at the interface

Solving for {T_{m} will give the temperature at the interface:

\frac{q}{A}=\frac{k_{fi} }{L_{fi} }(T_{fi} -T_{m})=\frac{k_{cb} }{L_{cb} }(T_{m} -T_{cb})

\frac{0.03}{0.05 }(25 -T_{m})=\frac{0.5}{0.2}(T_{m} -0})

15 -0.6T_{m}=2.5T_{m}

3.1T_{m}=15

T_{m}=4.8

3 0
4 years ago
⚠️Answer needed quick!!⚠️
Allisa [31]

Answer:

A

Explanation:

3 gifts

gift cost = x

$150 total to spend

$60 left after spending

5 0
3 years ago
The acceleration (in m/s^2) of a linear slider (undergoing rectilinear motion) within a If the machine can be expressed in terms
Inga [223]

Answer:

47.91 sec

Explanation:

it is given that \alpha =\frac{1}{4v^{2}}

at t=0 velocity =0 ( as it is given that it is starting from rest )

we have to find time at which velocity will be 3.3 \frac{m}{sec^{2}}

we know that \alpha =\frac{dv}{dt}=\frac{1}{4v^{2}}

4v^{2}dv=dt

integrating both side

\frac{4v^{3}}{3}=t+c---------------eqn 1

at t=o it is given that v=0 putting these value in eqn 1 c=0

so \frac{4v^{3}}{3}=t

when v=  3.3 \frac{m}{sec^{2}}

t=\frac{4}{3}\times 3.3^{3}

=47.91 sec

6 0
4 years ago
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