Answer:
50% probability of Pp (purple) or pp (white) genotype.
Explanation:
P = purple gene
p = white gene
Punnet squares show the possible genotypes and probabilities of each genotype in the offspring of a cross:
Purple flower genotype (heterozygous) = Pp
White flower genotype = pp
Punnet Square:
![\left[\begin{array}{ccc}&P&p\\p&Pp&pp\\p&Pp&pp\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26P%26p%5C%5Cp%26Pp%26pp%5C%5Cp%26Pp%26pp%5Cend%7Barray%7D%5Cright%5D)
Potential genotypes for offspring are Pp and pp;
According to the Punnett square, 2 of 4 offspring will have the Pp genotype and the other 2 will have pp genotypes;
This means 2 should be purple and 2 white;
Or, there is a 50% chance of having either genotype, of being purple or white.
An educated guess that is aslo posed as a tentative explanation is called a hypothesis.
Answer:
Option 1, 0
Explanation:
Complete question
Flower color in the varieties of pea plants studied by Mendel is controlled by alleles at a single locus. A group of peas homozygous for purple flowers is grown in a garden. All flowers are purple, yet there is some variation in the intensity of the purple color. The estimated heritability for this observed variation in flower color would be
- 0.
- 0.5.
- 0.75.
- 1.
- Cannot be determined without additional information
Solution
Given all the pea plants in the garden are homozygous purple (PP)
If we cross two PP parents, the following offspring will be produces
PP * PP
PP, PP, PP, PP
This means that all offspring are also homozygous purple.
Thus, chances of inheriting variation in the purple color of offspring are negligible. However, the variation in their color can be due to their individual interaction with the variable factors in the environment
Hence, option 1, 0 is correct
Answer:
d
Explanation:
bc it’s the deepest part so it is gonna take longer to heat up.
