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tester [92]
3 years ago
9

By the end of this lab, you will determine whether you should add cocoa mix (a solid) before or after heating water (liquid) to

make hot chocolate. State a broad question about solubility whose answer would help you determine this.
Chemistry
2 answers:
nikitadnepr [17]3 years ago
6 0
<span>For this lab experiment , the broad question to ask is "what is the solubility of the cocoa mix when mix with hot or cold water". The consistency that will be formed when cocoa mix are dissolved in hot or cold water will give an answer when best to add the cocoa.</span>
irinina [24]3 years ago
6 0

Answer:

format: “What is the effect of X on Y?”

materials: solid dissolved in a liquid

independent variable: temperature

dependent variable: solubility

Explanation:

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How are pH and pOH ?
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Answer:

B. pOH = 14 - pH and D. pH = 14 - pOH.

Explanation:

Hello,

In this case, we must remember that pH and pOH are referred to a measure of acidity and basicity  respectively, since pH accounts for the concentration of H⁺ and pOH for the concentration of OH⁻ in a solution. In such a way, since the maximum scale is 14, we say that the addition between the pH and pOH must be 14:

pH+pOH=14

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Which of the following is a solution?
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5 0
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Read 2 more answers
What mass in grams of a molecular substance (molar mass = 50.0 g/mol) must be added to 500 g of water to produce a solution that
Lera25 [3.4K]

<u>Answer:</u> The mass of the substance that must be added is 75.2 grams.

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{boiling point of solution}-\text{boiling point of pure solution}

\Delta T_b = ? °C

Boiling point of pure water = 100°C

Boiling point of solution = 101.54°C  

Putting values in above equation, we get:

\Delta T_b=(101.54-100)^oC=1.54^oC

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\Delta T_b=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_b = 1.54°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.512°C/m.g

m_{solute} = Given mass of solute = ? g

M_{solute} = Molar mass of solute = 50.0 g/mol

W_{solvent} = Mass of solvent (water) = 500 g

Putting values in above equation, we get:

1.54^oC=1\times 0.512^oC/m\times \frac{m_{solute}\times 1000}{50.0g/mol\times 500}\\\\m_{solute}=\frac{1.54\times 50.0\times 500}{1\times 0.512\times 1000}=75.2g

Hence, the mass of substance that must be added is 75.2 grams.

3 0
3 years ago
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