The compound is Octane since it has 8 carbons on the parent chain and has only single carbon to carbon bonds.
Molarity = mol/L
(0.5M) = (2mol)/L
(2mol)/(0.5M) = L
4 liters
Answer:
The overview of the subject is outlined underneath in the summary tab.
Explanation:
- The molar ratio seems to be essentially a balanced chemical equilibrium coefficient that implies or serves as a conversion factor for the product-related reactants.
- This ratio just says the reactant proportion which reacts, but not the exact quantity of the reacting product. Consequently, the molar ratio should only be used to provide theoretical instead of just a definite mass ratio.
Answer:
4.27
Explanation:
Let's consider the dissociation of a generic monoprotic acid.
HA(aq) → H⁺(aq) + A⁻(aq)
The pH is 2.36. The concentration of H⁺ is:
pH = -log [H⁺]
[H⁺] = antilog -pH
[H⁺] = antilog -2.36 = 4.37 × 10⁻³ M
We know that the concentration of the acid Ca = 0.3535 M. We can find the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]²/Ca
Ka = (4.37 × 10⁻³)²/0.3535
Ka = 5.40 × 10⁻⁵
The pKa is:
pKa = -log Ka = -log 5.40 × 10⁻⁵ = 4.27
The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
