2 years ago

Change 176°F to the Celsius and Kelvin scales

Physics

1 answer:

sveta [45]2 years ago

3 0

200 is the kelvin your welcome

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Find the mass if the force is 18 N and the acceleration is 2 m/s2.

Flura [38]

Answer:

<h3>The answer is 9 kg</h3>

Explanation:

To find the mass given the force and acceleration we use the formula

$m = \frac{f}{a} \\$

where

f is the force

a is the acceleration

We have

f = 18 N

a = 2 m/s²

We have

$m = \frac{18}{2} \\$

We have the final answer as

Hope this helps you

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2 years ago

What is the length of an aluminum rod at 65Â°C if its length at 15Â°C is 1.2 meters? A. 0.00180 meter B. 1.201386 meters C. 1.2

Deffense [45]

Answer:

Option B is the correct answer.

Explanation:

Thermal expansion

$\Delta L=L\alpha \Delta T$

L = 1.2 meter

ΔT = 65 - 15 = 50°C

Thermal Expansion Coefficient for aluminum, α = 24 x 10⁻⁶/°C

We have change in length

$\Delta L=L\alpha \Delta T=1.2\times 24\times 10^{-6}\times 50=1.44\times 10^{-3}m$

New length = 1.2 + 1.44 x 10⁻³ = 1.2014 m

Option B is the correct answer.

3 0

3 years ago

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A camper stands in a valley between two parallel cliff walls. He claps his hands and notices that the echo from the nearby wall

Stells [14]

5,658 ft is your answer I believe

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2 years ago

A 65 Kg skier starts at rest at the top of a 150 m long hill that has an incline of 28 degrees. How fast will she be going at th

yan [13]

Answer:

34 m/s

Explanation:

Potential energy at top = kinetic energy at bottom + work done by friction

PE = KE + W

mgh = ½ mv² + Fd

mg (d sin θ) = ½ mv² + Fd

Solving for v:

½ mv² = mg (d sin θ) − Fd

mv² = 2mg (d sin θ) − 2Fd

v² = 2g (d sin θ) − 2Fd/m

v = √(2g (d sin θ) − 2Fd/m)

Given g = 9.8 m/s², d = 150 m, θ = 28°, F = 50 N, and m = 65 kg:

v = √(2 (9.8 m/s²) (150 m sin 28°) − 2 (50 N) (150 m) / (65 kg))

v = 33.9 m/s

Rounded to two significant figures, her velocity at the bottom of the hill is 34 m/s.

8 0

3 years ago

The force involves the attraction between objects with mass. Strong nuclear. Gravitational. Electromagnetic. Weak nuclear

Viktor [21]

The answer is Gravitational.

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Change 176°F to the Celsius and Kelvin scales​

Change 176°F to the Celsius and Kelvin scales