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Paladinen [302]
3 years ago
6

Assuming that the density of air is 1.3 g/l, how many grams of carbon monoxide are in 1.0 l of air at the maximum allowable conc

entration?
Physics
1 answer:
Monica [59]3 years ago
4 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>35x1.3/1000000 = 0.0000455g = 0.0455 mg = 45.5 microgram/L</span>


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That 1.5 kg brick falls to the ground. What is the kinetic energy when the brick is moving at 26 m/s? Formula: Variables: Work w
Tresset [83]

Answer:

<h2>507 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.5 \times  {26}^{2}  \\  =  \frac{1}{2}  \times 1.5 \times 676 \\  = 1.5 \times 338  \\ = 507

We have the final answer as

<h3>507 J</h3>

Hope this helps you

5 0
3 years ago
Help Please
densk [106]

Answer:

Energy=3.1times 10^-17 J

Rest mass: 6.2 kg

Speed: 47.5 m/s

Wavelength: 2.659 times 10^-6

Momentum: 67.3 kg(m/s)

Explanation:

3 0
3 years ago
Section 2.2
Feliz [49]

Answer:

Speed changes at the rate of 24 m/s for each second over time.

Explanation:

We are told the object's acceleration is equal to 24 m/s²

Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.

Thus, we can rephrase the acceleration in this question to mean;

Speed changes at the rate of 24 m/s for every second with time.

6 0
3 years ago
Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

Given

Both cars mass is m

and solving problem in Vertical and horizontal direction

considering + y and +x to be positive and u be the final velocity of system

Conserving Momentum in Vertical direction

m(2v)+m(-vsin\phi )=2m(ucos\theta )

2ucos\theta =v(2-sin\theta )------1

Conserving momentum in x direction

mvcos\phi =2musin\theta-----2

squaring and adding 1 &2

(2u)^2=(2v-vsin\phi )^2+(vcos\phi )^2

4u^2=4v^2+v^2-4v^2sin\phi

4u^2=5v^2-4v^2sin\phi

u=\frac{v}{2}\sqrt{5-4sin\phi }

7 0
2 years ago
How does the value of the electrostatic force vary with the distance between them?
MariettaO [177]
The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.
5 0
2 years ago
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