1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ZanzabumX [31]
4 years ago
10

Peter throws a snowball at his car parked in the driveway. The snowball disintegrates as it hits the car. By Newton’s third law,

you know that both the car and the snowball exert a force on each other. What can you say about the magnitude of the forces exerted by the snowball and the car?. . A. The force exerted by the car is more than the force exerted b y the snowballl.. B. The force exerted by the car is less than the force exerted by the snowball. . C. The force exerted by the car is equal to the force exerted by the snowball. . D. The force exerted by the car is zero.
Physics
2 answers:
Lubov Fominskaja [6]4 years ago
8 0

Answer:

C. The force exerted by the car is equal to the force exerted by the snowball.

Explanation:

Newton's third law of motion states that:

" When an object A exerts a force on object B, then object B exerts an equal and opposite force on object B". These two forces are called action and reaction, and the law states that the two forces are equal in magnitude, and opposite in direction.

In this problem, we are considering the force exerted by snowball on the car: we can say that this is the action force. Therefore, the force exerted by the car on the snowball is the reaction. Newton's third law states that the two forces are equal in magnitude: therefore, the only correct option can be

C. The force exerted by the car is equal to the force exerted by the snowball. .

tamaranim1 [39]4 years ago
3 0
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
You might be interested in
9. When considering a magnet's force of attraction over a known distance, you would expect the strength of attraction 4 inches a
slavikrds [6]

Answer: B. 16 times

Explanation:

The mathematic expression for a magnetic force F_{M} between two magnets is:

F_{M}=K_{M}\frac{m_{1}m_{2}}{r^{2}}   (1)

Where:

K_{M} is a constant

{m_{1} and {m_{2} are the magnetic charges, which depends on the size of each magnet

r is the distance beteween both magnets

As we can see, this force in inversely proportional to the square of the distance. This means that if we increase the distance, the magnetic force will decrease.

Now, if we increase this value by 4 inches from 1 inch:

F_{M}=K_{M}\frac{m_{1}m_{2}}{{(4)}^{2}}   (2)

F_{M}=K_{M}\frac{m_{1}m_{2}}{16}   (3)

This means the strength of attraction will be 16 times weaker.

3 0
4 years ago
How far (in meters) above the earth's surface will the acceleration of gravity be 85.0 % of what it is on the surface?
suter [353]

Answer:

X = 6910319.7 m

Explanation:

let X be the distance where the acceleration of gravity is 85% of what it is on the surface and g1 be the acceleration of gravity at the surface and g2 be the acceleration of gravity at some distance X above the surface.

on the surface of the earth, the gravitational acceleration is given by:

g1 = GM/(r^2) = [(6.67408×10^-11)(5.972×10^24)]/[(6371×10^3)^2] = 9.82 m/s^2

at X meters above the earth's surface, g2 = 85/100(9.82) = 8.35m/s^2

then:

g2 = GM/(X^2)

X^2 = GM/g2

   X =  \sqrt{GM/g2}

       = \sqrt{(6.67408×10^-11)(5.972×10^24)/ 8.35

       = 6910319.7 m

Therefore, the acceleration of gravity becomes 85% of what it is on the surface at  6910319.7 m .

4 0
3 years ago
In a ballistics test at the police station an officer
posledela
You times the 6 by the 350 duvided 1.8
7 0
3 years ago
A 3.00 cm diameter coin rolls up a 30.0 degree incline plane. The coin starts with an initial angular speed of 60.0 rad/s in a s
yanalaym [24]

Answer:

The coin roll up to 11.57 cm at 30° incline plane.

Explanation:

Given that,

Diameter = 3.00 cm

Angle = 30.0 °

Angular speed = 60.0 rad/s

We need to calculate the length

Using conservation of energy

\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2=mgh

\dfrac{1}{2}mr^2\omega^2+\dfrac{1}{2}\times(0.4mr^2)\times\omega^2=mgl\sin\theta

Put the value into the formula

\dfrac{1}{2}\times(1.5\times10^{-2})^2\times(60.0)^2+\dfrac{1}{2}\times0.4\times(1.5\times10^{-2})^2\times(60.0)^2=9.8\times l\sin30

l\sin30=\dfrac{0.567}{9.8}

l=2\times\dfrac{0.567}{9.8}

l=0.1157\ m

Hence, The coin roll up to 11.57 cm at 30° incline plane.

8 0
4 years ago
Unpolarized light enters a polarizer with vertical polarization axis. The light that passes through passes another polarizer wit
mylen [45]

Answer:

  I = 0.2934 I₀

Explanation:

The expression that governs the transmission of polarization is

         I = I₀ cos² θ

Let's apply this to our case, when the unpolarized light enters the first polarized, the polarized light that comes out has the intensity of

        I₁ = I₀ / 2

this is the light that enters the second polarizer

        I = I₁ cos² θ  

         

we substitute

        I = I₀ / 2 cos² 40

        I = I₀ 0.2934

        I = 0.2934 I₀

4 0
4 years ago
Other questions:
  • State the universal law of gravitation
    7·1 answer
  • Which of the following statements is true about transverse waves?
    12·1 answer
  • What is the difference between heat and temperature
    10·1 answer
  • As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i
    14·2 answers
  • What is mean by the net displacement in transverse wave
    10·1 answer
  • How is this formula ( Rt= r1 x r2 / r1 + r2) which is used to calculate total resistance of two parallel resistors found from th
    14·1 answer
  • Which of the following statements is correct?
    9·1 answer
  • Two flat glass surfaces are separated by a 150-nm gap of air.
    11·1 answer
  • What is the car average speed between 0's and 5 s
    5·1 answer
  • Which of the following is correct based on the given illustration?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!