Answer:
-589.05 J
Explanation:
Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner
So, W = ΔK
W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)
So, substituting the values of the variables into the equation, we have
W = 1/2m(v₁² - v₀²)
W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)
W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)
W = 1/2 × 72.9 kg(-16.1604 m²/s²)
W = 1/2 × (-1178.09316 kgm²/s²)
W = -589.04658 kgm²/s²
W = -589.047 J
W ≅ -589.05 J
There is a a thing. so you use the scientific method by
The observation, measuring, and the experiment. also the formulation and then testing of your hypothesis
Can you please reword your question I can’t understand
-- "Work" is the product of (force exerted on the object) x (distance the object moves in the direction of the force).
Since the orbit is a circle, the gravitational force toward the center is always perpendicular to the orbit. The object never moves in the direction of the force. If it did, it wouldn't be 'R' away from the center of the circle.
So the product of (gravitational force) x (distance in the direction of the force) is always zero.
-- Even if the orbit ISN't a circle . . . there are some parts of the orbit that aren't quite perpendicular to the gravitational force. If the satellite is traveling through one of those parts AND getting closer to the central body, then gravity is doing positive work on the satellite. If the satellite is traveling through one of those parts and getting FARTHER from the central body, then the satellite is the one doing positive work, and gravity is doing 'negative work'. The work done by gravity ... and the work done by the satellite ... is zero over a complete revolution, although not zero at every point.
This is exactly the definition of a "Conservative Force" ... a force that does zero work through one trip around any CLOSED path. Gravity is a conservative force, and so is the Electrostatic force.
Answer:
B
Explanation:
i did this in like 7th grade hope its right