1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ZanzabumX [31]
3 years ago
10

Peter throws a snowball at his car parked in the driveway. The snowball disintegrates as it hits the car. By Newton’s third law,

you know that both the car and the snowball exert a force on each other. What can you say about the magnitude of the forces exerted by the snowball and the car?. . A. The force exerted by the car is more than the force exerted b y the snowballl.. B. The force exerted by the car is less than the force exerted by the snowball. . C. The force exerted by the car is equal to the force exerted by the snowball. . D. The force exerted by the car is zero.
Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

C. The force exerted by the car is equal to the force exerted by the snowball.

Explanation:

Newton's third law of motion states that:

" When an object A exerts a force on object B, then object B exerts an equal and opposite force on object B". These two forces are called action and reaction, and the law states that the two forces are equal in magnitude, and opposite in direction.

In this problem, we are considering the force exerted by snowball on the car: we can say that this is the action force. Therefore, the force exerted by the car on the snowball is the reaction. Newton's third law states that the two forces are equal in magnitude: therefore, the only correct option can be

C. The force exerted by the car is equal to the force exerted by the snowball. .

tamaranim1 [39]3 years ago
3 0
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
You might be interested in
A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
elena-14-01-66 [18.8K]

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

4 0
3 years ago
Basic explanation of the scientific method
igomit [66]
There is a a thing. so you use the scientific method by
The observation, measuring, and the experiment. also the formulation and then testing of your hypothesis 
5 0
3 years ago
If you stung by a honey bee you are <br>said with baking soda why<br>?​
Karolina [17]
Can you please reword your question I can’t understand
4 0
3 years ago
A satellite of mass M moves in a circular orbit of radius R at a constant speed v around the Earth which has mass ME.
Gwar [14]

-- "Work" is the product of (force exerted on the object) x (distance the object moves in the direction of the force).

Since the orbit is a circle, the gravitational force toward the center is always perpendicular to the orbit.  The object never moves in the direction of the force.  If it did, it wouldn't be 'R' away from the center of the circle.

So the product of (gravitational force) x (distance in the direction of the force) is always zero.

-- Even if the orbit ISN't a circle . . . there are some parts of the orbit that aren't quite perpendicular to the gravitational force.  If the satellite is traveling through one of those parts AND getting closer to the central body, then gravity is doing positive work on the satellite.  If the satellite is traveling through one of those parts and getting FARTHER from the central body, then the satellite is the one doing positive work, and gravity is doing 'negative work'.  The work done by gravity ... and the work done by the satellite ... is zero over a complete revolution, although not zero at every point.

This is exactly the definition of a "Conservative Force" ... a force that does zero work through one trip around any CLOSED path.  Gravity is a conservative force, and so is the Electrostatic force.

3 0
3 years ago
Which type of force occurs between two objects at a distance?
Serhud [2]

Answer:

B

Explanation:

i did this in like 7th grade hope its right

5 0
3 years ago
Read 2 more answers
Other questions:
  • How are the mass and weight an object related? Include a description with words and a equation.
    9·1 answer
  • Width, height, thickness and thermal conductivity of a single pane window and the air space of a double pane window. Representat
    6·1 answer
  • A chemical reaction that has the general formula of AB + C → CB + A is best classified as a reaction.
    14·2 answers
  • Most of the universe is believed to be ______
    7·2 answers
  • A tennis player hits a 1.45 kg tennis ball with a racket of mass 2.5 kg. If he hits the ball with a velocity of 7.5 m/s and then
    11·1 answer
  • If Mars were the same size as Mercury (instead of its actual size), which surface features would it have?
    7·1 answer
  • The resistance of a fluid to flow is referred to as
    5·1 answer
  • The velocity of an object with mass = 2kg is given as a function of time:
    6·1 answer
  • Please help me with this
    12·2 answers
  • The same girl in number 3 (above) pushes another friend on the same skateboard.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!