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ZanzabumX [31]
3 years ago
10

Peter throws a snowball at his car parked in the driveway. The snowball disintegrates as it hits the car. By Newton’s third law,

you know that both the car and the snowball exert a force on each other. What can you say about the magnitude of the forces exerted by the snowball and the car?. . A. The force exerted by the car is more than the force exerted b y the snowballl.. B. The force exerted by the car is less than the force exerted by the snowball. . C. The force exerted by the car is equal to the force exerted by the snowball. . D. The force exerted by the car is zero.
Physics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer:

C. The force exerted by the car is equal to the force exerted by the snowball.

Explanation:

Newton's third law of motion states that:

" When an object A exerts a force on object B, then object B exerts an equal and opposite force on object B". These two forces are called action and reaction, and the law states that the two forces are equal in magnitude, and opposite in direction.

In this problem, we are considering the force exerted by snowball on the car: we can say that this is the action force. Therefore, the force exerted by the car on the snowball is the reaction. Newton's third law states that the two forces are equal in magnitude: therefore, the only correct option can be

C. The force exerted by the car is equal to the force exerted by the snowball. .

tamaranim1 [39]3 years ago
3 0
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
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A 1.5m wire carries a 7 A current when a potential difference of 68 V is applied. What is the resistance of the wire?
PSYCHO15rus [73]

Working...

length of wire L = 1.5 m

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3 years ago
The breaking car had 10,000 J of kinetic energy before breaking after breaking it had 2000 J of kinetic energy. How much thermal
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Kinetic energy loss by car = thermal energy gained by brakes.

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The Kinetic energy loss by car can be expressed as;

∆K.E = K.E1 - K.E2

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