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enot [183]
2 years ago
9

Write an absolute value equation that has one solution of 17

Mathematics
1 answer:
erica [24]2 years ago
5 0

Answer:

|x| - 17 = 0

Step-by-step explanation:

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What’s 2x+y=4 in slope intercept form
PIT_PIT [208]
Y = - 2x + 4

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3 years ago
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-2x + y = 5 <br><br> what does y equal and how did you solve it?
Olin [163]

Answer:

y=2x+5

Step-by-step explanation:

Let's solve for y.

−2x+y=5

Step 1: Add 2x to both sides.

−2x+y+2x=5+2x

y=2x+5

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3 years ago
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(Y+3)(y^2-3y+9)<br><br> A. Y^3+27<br> B. Y^3-27<br> C. Y^3-6y^2+27<br> D. Y^3+6y^2+27
KonstantinChe [14]

Answer:

A) y^3+27

Step-by-step explanation:

There are two ways of solving this problem:

1. Recognizing this as the factored form of the sum of perfect cubes

2. Distribute and add the like terms.

1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:

(y+3)(y^2-3y+9)=y(y^2-3y+9)+3(y^2-3y+9)

y(y^2-3y+9)+3(y^2-3y+9)=y^3-3y^2+9y+3y^2-9y+27

After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:

y^3-3y^2+9y+3y^2-9y+27=y^3+27

2. You know how you can factor the difference of perfect squares?

As an example:

a^2-b^2=(a+b)(a-b)

Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:

a^3+b^3=(a+b)(a^2-ab+b^2)

a^3-b^3=(a-b)(a^2+ab+b^2)

Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27

6 0
2 years ago
What polygon is obtained by graphing the given system of inequalities? What is the area of the polygon bounded by the inequaliti
aalyn [17]
Hello,

Vertex are:
(1,1),(6,1),(1,4),(6,4=
Area=(6-1)*(4-1)=5*3=15

8 0
3 years ago
Can someone please help me ASAP
garri49 [273]

y=4-x^2\\x-y=2 \\  \\ y = 4 -  {x}^{2}  \\ x = 2 + y \\  \\ y = 4 -  {(2 + y)}^{2}  \\  {y}^{2}  + 5y = 0 \\ y(y + 5) = 0 \\ y = 0 \\ y =  - 5

x = 2 + 0 = 2

x = 2 + ( - 5) =  -3

5 0
3 years ago
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