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DIA [1.3K]
2 years ago
10

4 boys weighed themselves in different pairs and alone. The weights of the pairs were 110kg, 112 kg, 113kg, 118kg, 121 kg, and t

he weight of one pair was lost. The total weight of the 4 boys was 230kg. What was the lost weight?
Mathematics
1 answer:
ioda2 years ago
5 0

Answer:

wafasgfawga

Step-by-step explanation:

wadfasgawsgasg

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Which function has a domain of all real numbers except x=pi/2+-npi?
OLga [1]
It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.
8 0
3 years ago
Read 2 more answers
Find the exact value of sin(255∘)
Masteriza [31]

Check the picture below.

\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}

5 0
2 years ago
Will the variable be the "part" or the "whole"? remember, earlier he said "is over of = part over whole".
Helga [31]

Answer:

The variable is usually the unknown part of the whole.

5 0
1 year ago
Find the average rate of change of the function defined by the following table. x y -2 -5 2 35 6 75 10 115
Pani-rosa [81]

By definition we have that the average rate of change of the function is:

 AVR =  \frac{f(x2) - f(x1)}{x2 - x1}

 Evaluating the function for the complete interval we have that the AVR is given by:

 AVR = \frac{115 - (-5)}{10 - (-2)}

 Rewriting we have:

 AVR = \frac{115+5}{10+2}

 Simplifying the expression we have:

 AVR = \frac{120}{12}

 AVR = 10

 Answer:

 the average rate of change of the function defined by the table is:

 AVR = 10

6 0
2 years ago
2/3 of my cats plus three
gladu [14]
My answer -

3 2/3
Wow you have allot of cats LOL!!!

P.S
Have an AWESOME LGBT DAY !!! :)
3 0
2 years ago
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