Assuming that their exam success is independent then
P(both fail) = 1/4 x 2/5 = 2/20 or 1/10
1, 1.84+2= 1.84+2.00=3.84
3, 0.90+2= 0.90+2.00 = 2.90
4, 0.5+5= 0.5+5.0=5.5
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Theoretical probability is based on the likelihood of events.
if a coin is flipped 20 times, and it has landed on heads 4 times, theres a 50% chance it would land on heads the 5th time.
it could be that heads gets more than tails or it could be vise versa.
The probability of getting two heads is 1 in 4.
(t^2+1)^100
USE CHAIN RULE
Outside first (using power rule)
100*(t^2+1)^99 * derivative of the inside
100(t^2+1)^99 * d(t^2+1)
100(t^2+1)^99 * 2t
200t(t^2+1)^99
