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attashe74 [19]
3 years ago
10

1. The two images below show the area swept out by the same planet during two separate time spans. If the first picture represen

ts the area swept out during a time
of 'A' days and the second represents the area swept out during a time of "B* days, which of the following statements is true about A and B? Pls help

Physics
1 answer:
raketka [301]3 years ago
8 0

Answer:

its A

Explanation:

took the test

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Copernicus incorrectly assumed that the planets?
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Nicholas Copernicus correctly assumed that the planets revolved around the sun but he incorrectly assumed that the planets followed a perfect circle orbit around the sun. It was later on discovered by Johannes Kepler that the planets moved around the sun following an elliptical orbit.
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La velocidad del sonido en el aire es 340 m/s. Desde que se produjo el relámpago hasta que se oyó el trueno han transcurrido 8 s
scoundrel [369]

Answer:

Distancia = 42.5 metros

Explanation:

Dados los siguientes datos;

Velocidad del sonido = 340 m/s

Tiempo = 8 segundos

Para encontrar la distancia desde la que se escuchó el sonido;

Distancia = velocidad/tiempo

Sustituyendo en la fórmula, tenemos;

Distancia = 340/8

Distancia = 42.5 metros

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How many atoms of each element are in the chemical formula NH4NO3?
Igoryamba
 <span>2 Nitrogen, 4 Hydrogen, 3 Oxygen 

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4 0
3 years ago
Read 2 more answers
Two asteroids collide and stick together. The first asteroid has mass of 1.50 × 104 kg andis initially moving at 0.77 × 103 m/s.
KengaRu [80]

Answer:

Magnitude 900m/s, direction 12.8° respect to the velocity of the first asteroid.

Explanation:

This is a perfectly inelastic collision, because the two asteroids stick together at the end. That means that the kinetic energy doesn't conserves, but the linear momentum does. But, since the velocities of the asteroids have different directions, we have to break down them in components. For convenience, we will take the direction of the first asteroid as x-axis, and its perpendicular direction  (in the plane of the two velocity vectors) as y-axis. So, we have that:

p_{1ox}+p_{2ox}=p_{fx}\\\\p_{2oy}=p_{fy}

And, since p=mv, we get:

m_1v_{1o}+m_2v_{2o}\cos\theta=(m_1+m_2)v_{fx}\\\\m_2v_{2o}\sin\theta=(m_1+m_2)v_{fy}

Solving for v_fx and v_fy, and calculating their values, we get:

v_{fx}=\frac{m_1v_{1o}+m_2v_{2o}\cos\theta}{m_1+m_2}\\\\\implies v_{fx}=\frac{(1.50*10^{4}kg)(0.77*10^{3}m/s)+(2.00*10^{4}kg)(1.02*10^{3}m/s)\cos20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=878m/s\\\\\\v_{fy}=\frac{m_2v_{2o}\sin\theta}{m_1+m_2}\\\\\implies v_{fy}=\frac{(2.00*10^{4}kg)(1.02*10^{3}m/s)\sin20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=199m/s

Now, the final speed can be calculated using the Pythagorean Theorem:

v_f=\sqrt{v_{fx}^{2}+v_{fy}^{2}} \\\\\implies v_f=\sqrt{(878m/s)^{2}+(199m/s)^{2}}=900m/s

And the direction \beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°can be obtained using trigonometry:

\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°

That means that the final velocity of the two asteroids has a magnitude of 900m/s and a direction of 12.8° with respect to the velocity of the first asteroid.

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A stone is thrown vertically upward from the roof of the building. Does the position of the stone depend on the location chosen
mel-nik [20]
Yes it depend course you throw the stone at the roof it can't came course it in the roof
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