4.0 ilynits per second Alaskan es muy du facial in the oscillates 1.99
Answer:
<h2>
650W/m²</h2>
Explanation:
Intensity of the sunlight is expressed as I = Power/cross sectional area. It is measured in W/m²
Given parameters
Power rating = 6.50Watts
Cross sectional area = 100cm²
Before we calculate the intensity, we need to convert the area to m² first.
100cm² = 10cm * 10cm
SInce 100cm = 1m
10cm = (10/100)m
10cm = 0.1m
100cm² = 0.1m * 0.1m = 0.01m²
Area (in m²) = 0.01m²
Required
Intensity of the sunlight I
I = P/A
I = 6.5/0.01
I = 650W/m²
Hence, the intensity of the sunlight in W/m² is 650W/m²
F = ma
Acceleration in this case is acceleration due to gravity so
a = 9.8 m/s^2
and mass = 0.57kg
So..
F = (0.57)(9.8)
F = 5.586 or 5.56 N
Force 1 = 10/1000 × 5 = 0.05 N
Force 2 = 20/1000 × 2 = 0.04 N
F1>F2
so the answer is Force 1