A cyclist is traveling 10 m/s with an acceleration of 6 m/s2. How fast is the cyclist traveling at the end of 20 seconds
1 answer:
Answer:
<em>The cyclist is traveling at 130 m/s</em>
Explanation:
<u>Constant Acceleration Motion </u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
The cyclist initially travels at 10 /s and it's accelerating at a=6m/s^2. We need to know the new speed when t= 20 seconds have passed.
Apply the above equation:
The cyclist is traveling at 130 m/s
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Answer:
Explanation:
given,
mass of block = 3 kg
spring constant k = 500 N/m
kinetic friction coefficient µk = 0.6
speed of block = 5 m/s
F = µk N
F = 0.6 x 3 x 9.8
F = 17.64 N
using energy conservation
250 x² + 17.64 x - 37.5 = 0
on solving
x = 0.354 m
graph is attached below
Answer:
v=30 m/s
Explanation:
h - height
g - acceleration due to gravity=10
t - time
v- velocity
45 = 5t²
t² = 9
t=3 seconds
v=g×t
v=10×3
v=30 m/s