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3 years ago

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According to Newton's 2nd law of motion, Jim can throw a _ farther than a _. tennis ball, basketball can of soda, liter

bottle of soda chair, couch all of the above

2 answers:

Butoxors [25]3 years ago

4 0

Answer:

All of the above

Explanation:

According to Newton's second law of motion,

$Force = Mass \times Acceleration$

If a certain force is applied on objects of different mass, the lighter object will travel farther and faster. All the options in the question have pairs where one object is lighter than other.

So, Jim can throw a <em>tennis ball</em> farther than a <em>basketball</em>. Jim can throw a <em>can of soda</em> farther than a <em>liter bottle of soda</em> and he can throw a <em>chair</em> farther than a <em>couch</em>.

chubhunter [2.5K]3 years ago

3 0

According to Newton's 2nd law of motion, Jim can throw a tennis ball farther than a <span>basketball</span>. The rest of the choices do not answer the question above.

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After pulling the string tight, Miguel talked into his aluminum can. Brian could hear Miguel's voice through the aluminum can at

Alex73 [517]

Answer:

option C is correct✅✅✅✅✅

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3 years ago

Model the concrete slab as being surrounded on both sides (contact area 24 m2) with a 2.1-m-thick layer of air in contact with a

Sloan [31]

Answer:

$\dot{Q} =1.5\ W$

Explanation:

Given that:

area of concrete slab, $A=24\ m^2$

thickness of the layer of air, $dx=2.1\ m$

temperature difference between the air and the concrete, $dT=5\ K (\rm difference\ will\ be\ same\ in\ K\ and\ ^{\circ}C)$

We have:

thermal conductivity of air at S.T.P., $k=26.24 \times 10^{-3}\ W.m^{-1}.K^{-1}$

<u>Now, according to Fourier's Law of conduction:</u>

$\dot{Q} =k.A.\frac{dT}{dx}$

putting the respective values:

$\dot{Q} =26.24 \times 10^{-3}\times 24\times \frac{5}{2.1}$

$\dot{Q} =1.5\ W$

5 0

3 years ago

A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane

umka2103 [35]

Answer:

466 km/h

255°

measured anticlockwise from the east direction

Explanation:

find the resultant velocity of a plane after a crosswind affects its motion. take the positive

x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are

<em>upx =</em> 0
<em>upy = 450 Km/ h</em>

<em>And for the wind.</em>

<em>uwx = - 120 Km/h</em>
<em>uwy = 0</em>

<em>The components for the r</em><em>esultant velocity </em><em>of the plane are given by</em>

<em>ux =upx + uwx = 0 - 120 Km/h = </em><u><em>- 120 Km/h</em></u>

<em>uy = upy + uwy = - 450 Km/h +0 = </em><u><em>- 450 Km/h</em></u>

<em>The </em><em>magnitude </em><em>of the resultant velocity is</em>

<em /> $\sqrt{(vx)^2+(vy)^2} =\sqrt{(-120lkm/h^2+(-450lkm/h)^2}$

= 466 km/h

Hope this helps u : )

7 0

1 year ago

The grocery store is 20 miles away

adoni [48]

Answer:

40mph

Explanation:

20miles .5 miles away if you go 20 mph you get there in a hour soo if you double to 40 mpg you get there in 0.5

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3 years ago

Read 2 more answers

You work for the city water department and need to pump 3400 liters/minute of water from a tank at ground level into a vented (i

umka21 [38]

Answer:

$P_E=46.2778\ kW$

$v=1.804\ m.s^{-1}$

Explanation:

Given:

flow rate of water, $\dot{V}=3400\ L.min^{-1}=3.4\ m^3.min^{-1}$

<em>∵Density of water is 1 kg per liter</em>

∴mass flow rate of water, $\dot{m}=3400\ kg.min^{-1}$

height of pumping, $h=75\ m$

efficiency of motor drive, $\eta=0.9$

diameter of pipe, $D =0.2\ m$

<u>Now the power required for pumping the water at given conditions:</u>

$P=\dot{m}.g.h$

$P=\frac{3400}{60} \times 9.8\times 75$

$P=41650\ W$

<u>Hence the electric power required:</u>

$P_E \times \eta=P$

$P_E \times 0.9=41650$

$P_E=46.2778\ kW$

<u>Flow velocity is given as:</u>

$v=\dot{V}\div a$

where: a = cross sectional area of flow through the pipe

$v=\frac{3.4}{60}\div (\pi.\frac{0.2^2}{4} )$

$v=1.804\ m.s^{-1}$

3 0

3 years ago