Answer:
'A' is the the point on the graph that shows a temperature of 40°C and the time of 25 minutes
Answer:
a) 0.049 m
b) Yes, increase
Explanation:
Draw a free body diagram.
In the y direction, there are three forces acting on the feeder. Two vertical components of the tension forces in each rope pulling up, and weight force pulling down.
Apply Newton's second law to the feeder in the y direction.
∑F = ma
2Ty − mg = 0
Ty = mg/2
Let's say the distance the rope sags is d. The trees are 4m apart, so the feeder is 2m horizontally from either tree. Using Pythagorean theorem, we can find the length of the rope on either side:
L² = 2² + d²
L = √(4 + d²)
Using similar triangles, we can write a proportion using the forces and distances.
Ty / T = d / L
Substitute:
(mg/2) / T = d / √(4 + d²)
Solve for d:
Td = mg/2 √(4 + d²)
T² d² = (mg/2)² (4 + d²)
T² d² = (mg)² + (mg/2)² d²
(T² − (mg/2)²) d² = (mg)²
d² = (mg)² / (T² − (mg/2)²)
d = mg / √(T² − (mg/2)²)
Given m = 2.4 kg and T = 480 N:
d = (2.4) (9.8) / √(480² − (2.4×9.8/2)²)
d = 0.049 m
b) If a bird lands on a feeder, this will increase the tension in the rope to support the bird's weight.
Answer:
Explanation:
The rest energy is the energy associated with the base ball at zero velocity which is expressed as
Note: the speed C is the speed of light which is expressed as 3*10^8
while the kinetic energy is the energy associated with the ball during its motion and is expressed as
the ratio can be expressed as
Answer:
it is a very good morning amor de g the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of 88th paragraph of the first paragraph
Explanation:
We need to apply the conservation law of linear momentum to two dimensions:
Let 
= momentum of the 1st ball
= momentum of the 2nd ball
In the x-axis, the conservation law can be written as
or
Since we are dealing with identical balls, all the m terms cancel out so we are left with
Putting in the numbers, we get
In the y-axis, there is no initial y-component of the momentum before the collision so we can write
or
Taking the ratio of the sine equation to the cosine equation, we get
or
Solving now for 
,
