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Annette [7]
3 years ago
7

Which statements describe how stars are born? Check all that apply. Stars are born in clouds of gas and dust called nebulas. The

gas and dust are pulled together by gravity. If the cloud that is pulled together has enough mass, a red giant is formed. The pulled-together cloud collapses and becomes hot and dense. Heat and pressure cause nuclear fusion, which signals the birth of a star.
Chemistry
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

1.Stars are born in clouds of gas and dust called nebulas.

2.The gas and dust are pulled together by gravity.

4.The pulled-together cloud collapses and becomes hot and dense.

5.Heat and pressure cause nuclear fusion, which signals the birth of a star.

Explanation:

prohojiy [21]3 years ago
6 0

Answer: 1.Stars are born in clouds of gas and dust called nebulas.

2.The gas and dust are pulled together by gravity.

3.Heat and pressure cause nuclear fusion, which signals the birth of a star.

Explanation:

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`I am holding a balloon containing 439 mL of gas over my fireplace. The temperature and pressure of the gas inside the balloon i
Andrew [12]

Answer:

- 0.07 °C

Explanation:

At constant pressure and number of moles, Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 439 mL  = 0.439 L ( 1 L = 0.001 mL )

V₂ = 0.378 L

T₁ = 317.15 K

T₂ = ?

Using above equation as:

\frac{0.439}{317.15}=\frac{0.378}{T_2}

T_2=\frac{0.378\cdot \:317.15}{0.439}=273.08\ K

The conversion of T(K) to T( °C) is shown below:

T( °C) = T(K) - 273.15  

So, <u>T = 273.08 - 273.15 °C = - 0.07 °C</u>

3 0
3 years ago
If the concentration of mercury in the water of a polluted lake is 0.250 μg (micrograms) per liter of water, what is the total m
aleksandr82 [10.1K]

Answer:

142.36 kg

Explanation:

volume of water in the lake = surface area x depth

= 18.5 x ( 1760 x 3 )² x 39 ft³

= 2.011 x 10¹⁰ ft³

= 2.011 x 10¹⁰ x 28.3168 liter .

= 56.945 x 10¹⁰ liter .

concentration of mercury = .25 x 10⁻⁶ g / liter

= 25 x 10⁻⁸ g / liter

= 25 x 10⁻¹¹ kg / liter

mass of mercury in the water of lake

= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg

= 142.36 kg .

8 0
2 years ago
Someone pls help me I will make you brain
Olegator [25]

Answer:

the second answer

Explanation:

5 0
3 years ago
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Which is smaller 25 mm or 25cm
umka21 [38]

Answer:

25 mm is smaller.

5 0
3 years ago
43. A stock glucose standard has a concentration of 1,000 mg/dL. A 1/5 dilution of this standard is made. What would be the fina
Nat2105 [25]

The final concentration of the diluted standard is 0.2 mg/dL.

<h3 /><h3>What is concentration of glucose standard after 1/5 solution?</h3>

Using the dilution formula:

  • C1V1 = C2V2

where

  • C1 is initial concentration
  • V1 initial volume
  • C2 is final concentration
  • V2 is final volume.

Assuming a final volume of 100 mL, and since a 1/5 dilution is made:

C1 = 1.00 mg/dL

V1 = 20

C2 = ?

V2 = 100 mL

C2 = C1V1/V2

C2 = 20 × 1/100

C2 = 0.2 mg/dL

Therefore, the final concentration of the diluted standard is 0.2 mg/dL.

Learn more about dilution at: brainly.com/question/24881505

6 0
2 years ago
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