When solid <span>iron (iii) hydroxide is dissolved into water, it ionizes or it dissociates into ions. These ions are the iron (iii) ions and the hydroxide ions. Iron(III) oxide is classified as a base when in aqueous solution since it produces hydroxide ions. It is a weak base so it does not completely dissociate into the solution. The dissociation equation would be:
Fe(OH)3 <-----> Fe3+ + OH-
To write a complete reaction, the reaction should be balanced wherein the number of atoms of each element in the reactant side and the product side should be equal. Also, the phases of the substances should be written. We do as follows:
</span>
Fe(OH)3 (s) <-----> Fe3+ (aq) + 3OH- (aq)
Molar mass Ra(OH)2 = 260 g/mol
<span>Moles = 987 g / 260 = 3.80 moles</span>
Explanation:
during this reaction this will produce 2 molecules of No
Answer:
1.05 mol
Explanation:
Step 1: Given data
- Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)
- Volume of solution (V): 395 mL (0.395 L)
Step 2: Calculate the moles of sulfuric acid (n)
We will use the following expression.
M = n/V
n = M × V
n = 1.325 mol/L × 0.395 L = 0.523 mol
Step 3: Calculate the moles of H⁺
H₂SO₄ dissociates completely according to the following equation.
H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻
The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.
Molar mass of NaHCO3 is 83.9. moles of Na...O3= 5.8/83.9
=0.0691
for every mole of Na..O3 there are 3 O
n(O) = n(NaHCO3) x3
= 0.207
mass of O is the moles x molar mass (16)
therefore the mass of O is 3.3 grams
