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e-lub [12.9K]
3 years ago
12

What volume would 75.0g of oxygen gas occupy

Chemistry
1 answer:
seropon [69]3 years ago
7 0

Answer:

Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.

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hram777 [196]
The mass decay rate is of the form
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e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

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m = 3000 e^{-0.0231*60} = 750 \, g

Answer: 750 g

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victus00 [196]
1. <span>The answer should be combustion

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</span>
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Read 2 more answers
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