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grigory [225]
3 years ago
10

Please help I need this fast

Physics
2 answers:
STALIN [3.7K]3 years ago
8 0

Answer:

0 m/sec

Explanation:

b/c they were at rest and initial means at rest ,at rest means 0 HOPE THIS HELPS

vredina [299]3 years ago
7 0
I’m pretty sure 0 m/secs is right, sorry if I’m wrong
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The answer is "3.83 \times 10^9 \ m"

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3 years ago
Describe a situation in your everyday life where you could use the scientific method. List all the steps of the scientific metho
emmainna [20.7K]

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8 0
4 years ago
A Venturi tube may be used as the inlet to an automobile carburetor. If an inlet pipe with a diameter of 2.0 cm diameter narrows
valkas [14]

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4 0
4 years ago
Read 2 more answers
What is the cell emf for the concentrations given? Express your answer using two significant figures.
alisha [4.7K]

Complete Question

A  voltaic cell is  constructed with two Zn^{2+}- Zn electrodes. The  two cell compartment have  [Zn^{2+}] =  1.6 \ M and  [Zn^{2+}] =  2.00*10^{-2} \  M respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is   E =  0.06 V

Explanation:

Generally from the question we are told that

   The  concentration of [Zn^{2+}] at the cathode is  [Zn^{2+}]_a =  1.6 \ M

    The  concentration of [Zn^{2+}] at the anode is [Zn^{2+}]_c =  2.00*10^{-2} \  M

Generally the the cell emf for the concentration is mathematically represented as

     E =  E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}

Generally the E^ois the standard emf of a cell, the value is  0 V

So

      E =  0  -  \frac{0.0591}{2}  * log[\frac{ 2.00*10^{-2}}{1.6} ]

=>      E =  0.06 V

4 0
3 years ago
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