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3 years ago

10

Jackson has $1.50 in quarters and dimes. Let x represent the number of quarters and y represent the number of dime. Find the dom

ain and range of this situation.

1 answer:

QveST [7]3 years ago

8 0

Answer:

3 dimes

Step-by-step explanation:

Part A: 0.10x + 0.25 = 0.80 (dimes are 10 cents or 0.10 dollars, quarters are 0.25 dollars)

Part B: Plug in what you DO know and solve the one you DON’T:

0.10x + 0.25(2) = 0.80

0.10x + 0.50 = 0.80. Subtract 0.50 from both sides:

0.10x = 0.30 (Divide both sides by 0.10)

x = 3

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Find an expression equivalent to the one shown below.

TEA [102]

Answer:

C) 1/6^32

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)^c = a^(b·c)

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

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Using these rules, your expression simplifies to ...

6^8·6^(10(-4)) = 6^8·6^-40 = 6^(8-40) = 6^-32 = 1/6^32

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3 years ago

What is b in terms of a and c?

aev [14]

Answer:

$b=\sqrt{c^2-a^2}$

Step-by-step explanation:

The given relation is

$c=\sqrt{a^2+b^2}$

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Isolate $b$ on one side of the equation;

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Or

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3 years ago

If a person studies for 8hrs a week. How long to they work each day

Andrew [12]

Answer:

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Step-by-step explanation:

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3 years ago

Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

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$c^2 = 16 + 36$

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Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

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$16 + 8a = 52 + 6^2$

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