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Alenkinab [10]
2 years ago
8

If 85.0 L of helium at 29.0°C is compressed to 32.0 L at constant pressure, what is the new temperature?

Chemistry
1 answer:
Feliz [49]2 years ago
3 0

Answer:

113.69°k

Explanation:

V1=85L of helium                         V2=32L

T1= 29°C +273= 302°K                 T2=?

     T2=<u>TIV2</u>

              V1

    T2=<u>(302)(32)</u>= <u>9664</u>

                85           85

    T2=  113.69°K

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Answer:

D) 1/2

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3 years ago
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Answer:

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mass balance:

0.10 m = [ C6H5COO- ] + [ C6H5COOH ].....(1)

charge balance:

[ H3O+ ] = [ C6H5COO- ] + [ OH- ] .......[ OH- ] : comes from water, it's not significant

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⇒ 0.10 M = [ H3O+ ] + [ C6H5COOH ]

⇒ [ C6H5COOH ] = 0.10 - [ H3O+ ]

⇒ Ka = [ H3O+ ]² / ( 0.1 - [ H3O+ ] ) = 6.5 E-5

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to learn more about party alliances go to -

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