How would you prepare a 0.1M solution of HCl starting with a 1.0M solution? Assume you want to prepare 100 ml of solution.

1 answer:

4 0

This question is a dilution problem. In order to prepare a certain concentration and volume from a stock solution, you have to use the equation,

M1V1 = M2V2

From the equation, you need to calculate the volume you need from the stock solution to be able to have the diluted concentration then dilute it to a certain volume.

(1.0 M) (V1) = (0.1 M) (100 mL)
V1 = 0.1 mL is needed from the 1.0 M HCl solution

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Read the following chemical equation: Ti + 2Cl2 → TiCl4 Which statement best identifies and describes the reducing agent in the

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Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.

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Firstly, we need to identify the reducing agent and the oxidizing agent.

The reducing agent: is the agent that has been oxidized via losing electrons.

The oxidizing agent: is the agent that has been reduced via gaining electrons.

Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.

So, Ti is the reducing agent because its oxidation state changes from 0 to +4.

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Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.

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