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2 years ago

Which of the following statements best describes the Lewis structure of CIO4 and ClO3?

Chemistry

1 answer:

mash [69]2 years ago

4 0

CIO4 statements best describe the Lewis structure.

<h3>What is Lewis Structure?</h3>

A Lewis Structure is a very simplified presentation of the valence shell electrons in a molecule. It is used to show how the electrons are organized around particular atoms in a molecule. Electrons are displayed as "dots" or for bonding electrons as a line between the two atoms.

Lewis structure does NOT endeavor to explain the geometry of molecules, how the bonds compose, or how the electrons are transmitted between the atoms.
It is the easiest and most limited theory on electronic format.Lewis systems show separately atom and its position in the structure of the molecule using its chemical symbol. Lines are drawn between atoms that are connected (pairs of dots can be used instead of sequences). Excess electrons that form lone pairs are defined as pairs of dots and are positioned next to the atoms.

To learn more about Lewis Structure, reffer:

brainly.com/question/7218689

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Is toothpaste suspension,colloid,solution?

natima [27]

Answer:

Collid

Explanation:

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saul85 [17]

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For many purposes we can treat methane as an ideal gas at temperatures above its boiling point of . Suppose the temperature of a

Elza [17]

Answer:

The volume decreases 5.5%

Explanation:

First, the question is incomplete, you are not giving the values of the temperatures and the pressure. However, I managed to find one similar question, and the given data is the temperature is lowered from 21 °C to -8°C, and the pressure decreased by 5%. If your data is different, you should only replace your data in the procedure, and you'll get an accurate result.

Now, with this data, let's see what we can do.

If this is an ideal gas, the equation to use is:

PV = nRT

Now, we know that this gas is suffering a decrease in temperature and pressure, but the moles stay the same so:

n₁ = n₂ = n

The constant R, is the same for both conditions. The only thing that differs here is the volume, temperature, and pressure. Therefore:

P₁V₁ = nRT₁ -----> n = P₁V₁ / RT₁

Doing the same with the pressure and volume 2 we have:

n = P₂V₂ / RT₂

Equalling both expressions and solving for V₂:

P₁V₁ / RT₁ = P₂V₂ / RT₂

V₂ = P₁T₂V₁ / P₂T₁

Now, as we know that P2 is 5% decreased from P1, so P2 = 0.95P1:

V₂ = P₁T₂V₁ / 0.95P₁T₁

The values of temperature in K:

T1 = 21+273 = 294 K

T2 = -8 + 273 = 265 K

Finally, let's calculate the volume:

V₂ = 264*P₁*V₁ / 294*0.95*P₁ ----> P cancels out

V₂ = 264V₁ / 294*0.95

V₁ = 0.945V₂

With this, we can day that Volume 2 decreases.

Now the percentage change would be using the following expression:

%V = (V₁ - V₂ / V₁) * 100

Replacing the data we have:

%V = V1 - 0.945V₁ / V₁

%V = 0.055V₁ / V₁ * 100

%V = 5.5%

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