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romanna [79]
3 years ago
9

4.True or false. P(E) + P(Ec) = 1.

Chemistry
1 answer:
iogann1982 [59]3 years ago
4 0
4.) True: 
Since
P(E) = 1 - P(Ec)
P(E)+P(Ec)=1 
If you think of it as the chances of you getting e or not getting e, then it's a 100% chance of either one happening. 
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Which of the following is true regarding nominal and real GDP?
spin [16.1K]

d) the only thing that can increase real GDP is an increase is output

hope this helps!

5 0
3 years ago
How much water will be required to dissolve 0.3g of benzoic acid at 95oC given that the solubility of BA at 95oC is 68.0g/L?
Ainat [17]
Write as a proportion, showing the relationship of both given information:
68.0g 0.3g
---------- = -----------
1L x ( your answer)

Cross multiply: 68.0g× X = 0.3g × 1L
68.0g (X)= 0.3g/L
Solve for X by dividing both sides by 68.0 g
68.0g (X) = 0.3g/L
------------- ------------------
68.0g 68.0g

Then enter into calculator 0.3/68 and that will be your solution. Make sure you round up.
6 0
2 years ago
Please help asap loll
BlackZzzverrR [31]

Explanation:

Metals -

  1. Left side of periodic table
  2. Malleable
  3. Ductile
  4. Good conductor
  5. Mostly solid
  6. Shinly lusture

Non-metals -

  1. Poor conductor
  2. Dull
  3. Brittle
  4. Right side of periodic table

Metalloids -

  1. Properties of metals and non-metals.
  2. Found on the 'staircase' of the periodic table.

5 0
3 years ago
Gaseous methane CH4 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is the t
Murrr4er [49]

Answer:

50.8 g

Explanation:

Equation of reaction.

CH_4 + 2O_2 \to CO_2 + 2H_2O

From the given information, the number of moles of methane = mass/ molar mass

= 15.4 g /  16.04 g/mol

= 0.960 mol

number of moles of oxygen gas = 90.3 g / 32 g/ mol

= 2.82 mol

Since 1 mol of methane requires 2 moles of oxygen

Then 0.960 mol of methane will require = 0.960 mol × 2 = 1.92 mol of oxygen gas

Thus, methane serves as a limiting reagent.

2.82 mol oxygen gas will result in 2.82 moles of water

So, the theoretical yield of water = moles × molar mass

= 2.82 mol × 18.01528 g/mol

= 50.8 g

8 0
2 years ago
How many grams of ca are needed to react completely with 2.20 L of a 4.50 m hcl solution
Dmitry_Shevchenko [17]
Ca + 2HCl = CaCl₂ + H₂

c=4.50 mol/l
v=2.20 l

n(HCl)=cv

m(Ca)/M(Ca)=n(HCl)/2

m(Ca)=M(Ca)cv/2

m(Ca)=40g/mol·4.50mol/l·2.20l/2=198 g

198 grams of Ca are needed

5 0
3 years ago
Read 2 more answers
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