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3 years ago

6

(SSS, SAS, AAS, ASA, HL) Help me plzzzz

1 answer:

-Dominant- [34]3 years ago

7 0

The answer is HL. We know this because it is a right triangle (:

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HELP PLS ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎ ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

VikaD [51]

Answer:

with what 0-0 are youy okay?

Step-by-step explanation:

8 0

3 years ago

mary has g+24.50 in her bank account. bobby has 7g- 52.34 in his bank account. How much do they have in all?

Gnoma [55]

A=850×(1+0.08)^(8)
A=1,573.29

Interest 1573.29-850=723.29

6 0

3 years ago

The total number of gallons of water in a tank, w, after t minutes is given in this table and the plot.

Katyanochek1 [597]

The equation showing the relationship between w and t is $w = 4t$

From the table, we have the following points:

(0,0) and (1,4)

Start by calculating the slope (m)

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

$m = \frac{4 -0}{1 -0}$

Simplify the numerator and the denominator

$m = \frac{4}{1}$

Divide 4 by 1

$m = 4$

The equation is then calculated as:

$w = m(t - t_1) + w_1$

This gives

$w = 4(t - 0) + 0$

Simplify

$w = 4t$

Hence, the equation is $w = 4t$

Read more about linear equations at:

brainly.com/question/14323743

4 0

3 years ago

Jason is pulling a box across the room. He is pulling with a force of 11 newtons and his arm is making a 37 angle with the horiz

MissTica

Force=10N

Angle=37

Vertical componenets:-

$\\ \sf\longmapsto Fsin\theta$

$\\ \sf\longmapsto 10sin38$

$\\ \sf\longmapsto 10(0.6)$

$\\ \sf\longmapsto 6N$

4 0

3 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

3 years ago