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MrRa [10]
3 years ago
13

The electron configuration for Helium (He) is shown below.

Chemistry
1 answer:
Alik [6]3 years ago
3 0
The first illustration
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In the covalent compound CH3, the Greek prefix used to represent the anion is Answer here​
Contact [7]

Answer:

Tri.

Explanation:

''Tri'' is the Greek prefix used to represent the CH3 because there are three hydrogen atoms to form the covalent compound so in Greek method ''Tri'' is used for three. In Greek system, there are certain names for prefixes such as ''di'' is used for two, ''tri'' is used for three, ''tetra'' is used for four etc. This method only provides information about the number of atoms that form the covalent compound.

3 0
3 years ago
Help me pleaseee, if you do tyy :)
ruslelena [56]
There is one atom of sulfur :)
4 0
3 years ago
A compound that is usually used as a fertilizer can also be used as a powerful explosive. the compound has the composition 35.00
maxonik [38]

Answer:

             Empirical Formula  =  NH₄NO₃ (Ammonium Nitrate)

Solution:

Step 1: Calculate Moles of each Element;

                      Moles of N  =  %N ÷ At.Mass of N

                      Moles of N  = 35.0 ÷ 14

                      Moles of N  =  2.5 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 59.96 ÷ 16

                      Moles of O  =  3.7475 mol


                      Moles of H  =  [100% - (%N + %O)] ÷ At.Mass of H

                      Moles of H  = [100% - (35.0 + 59.96)] ÷ 1.008

                      Moles of H  = [100% - 94.96] ÷ 1.008

                      Moles of H  = 5.04 ÷ 1.008

                      Moles of H  =  5 mol

Step 2: Find out mole ratio and simplify it;

                N                                        H                                     O

               2.5                                       5                                3.7475

            2.5/2.5                                5/2.5                          3.7475/2.5

                 1                                         2                                     1.5

Multiply Mole Ratio by 2,

                 2                                         4                                     3

Result:

         Empirical Formula  =  N₂H₄O₃

Or,

         Empirical Formula  =  NH₄NO₃

This empirical formula is also a Molecular Formula for Ammonium Nitrate a well known Fertilizer and often misused in the formation of Explosives.

4 0
3 years ago
Determine the number of bonding electrons and the number of nonbonding electrons in the structure of SI2. Enter the number of bo
mariarad [96]

Answer:

4, 16,

Explanation:

SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).

Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.

7 0
3 years ago
Hotosynthesis can be represented by 6CO2(g)+6H2O(l)⇌C6H12O6(s)+6O2(g) Which of the following will be false when the photosynthes
antoniya [11.8K]

Answer: Option (b) and (d) are correct.

Explanation:

An equilibrium reaction is defined as the reaction in which rate of forward reaction equals rate of backward reaction.

A photosynthesis reaction is the reaction in which plants in the presence of sunlight, water, and carbon dioxide make their own food.  

  • The amount of carbon dioxide consumed will be equal to the rate of formation of oxygen into the atmosphere.

Hence, the statement rate of formation of O_{2} is equal to the rate of formation of CO_{2} is true.

  • Concentration of oxygen may remain constant but it will not decrease. Hence, the statement concentration of O_{2} will begin decreasing, is false.
  • As both oxygen and carbon dioxide are present in an equilibrium reaction, So, their concentration will not change.

        Hence, the statement concentrations of CO_{2} and O_{2} will not change, is true.

  • Concentration of carbon dioxide and oxygen will also depend on the limiting reagent. So, it is not necessary that the concentrations of CO_{2} and O_{2} will be equal.

Some amount of carbon dioxide might escape out into the air.

Hence, the statement concentrations of CO_{2} and O_{2} will be equal, is false.

3 0
3 years ago
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