Answer:
Tri.
Explanation:
''Tri'' is the Greek prefix used to represent the CH3 because there are three hydrogen atoms to form the covalent compound so in Greek method ''Tri'' is used for three. In Greek system, there are certain names for prefixes such as ''di'' is used for two, ''tri'' is used for three, ''tetra'' is used for four etc. This method only provides information about the number of atoms that form the covalent compound.
There is one atom of sulfur :)
Answer:
Empirical Formula = NH₄NO₃ (Ammonium Nitrate)
Solution:
Step 1: Calculate Moles of each Element;
Moles of N = %N ÷ At.Mass of N
Moles of N = 35.0 ÷ 14
Moles of N = 2.5 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 59.96 ÷ 16
Moles of O = 3.7475 mol
Moles of H = [100% - (%N + %O)] ÷ At.Mass of H
Moles of H = [100% - (35.0 + 59.96)] ÷ 1.008
Moles of H = [100% - 94.96] ÷ 1.008
Moles of H = 5.04 ÷ 1.008
Moles of H = 5 mol
Step 2: Find out mole ratio and simplify it;
N H O
2.5 5 3.7475
2.5/2.5 5/2.5 3.7475/2.5
1 2 1.5
Multiply Mole Ratio by 2,
2 4 3
Result:
Empirical Formula = N₂H₄O₃
Or,
Empirical Formula = NH₄NO₃
This empirical formula is also a Molecular Formula for Ammonium Nitrate a well known Fertilizer and often misused in the formation of Explosives.
Answer:
4, 16,
Explanation:
SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).
Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.
Answer: Option (b) and (d) are correct.
Explanation:
An equilibrium reaction is defined as the reaction in which rate of forward reaction equals rate of backward reaction.
A photosynthesis reaction is the reaction in which plants in the presence of sunlight, water, and carbon dioxide make their own food.
- The amount of carbon dioxide consumed will be equal to the rate of formation of oxygen into the atmosphere.
Hence, the statement rate of formation of 
is equal to the rate of formation of 
is true.
- Concentration of oxygen may remain constant but it will not decrease. Hence, the statement concentration of will begin decreasing, is false.
- As both oxygen and carbon dioxide are present in an equilibrium reaction, So, their concentration will not change.
Hence, the statement concentrations of and will not change, is true.
- Concentration of carbon dioxide and oxygen will also depend on the limiting reagent. So, it is not necessary that the concentrations of and will be equal.
Some amount of carbon dioxide might escape out into the air.
Hence, the statement concentrations of and will be equal, is false.
