Help me pleaseee, if you do tyy :)

Carvone (C10H14O) is the main component of spearmint oil. It has a pleasant aroma and mint flavor. Carvone is often added to che

marta [7]

<u>Answer:</u> The mass of carbon in given amount of carvone is 47.52 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of carvone = 55.4 g

Molar mass of carvone = 150.22 g/mol

Putting values in equation 1, we get:

$\text{Moles of carvone}=\frac{55.4g}{150.22g/mol}=0.369mol$

The chemical formula of carvone is $C_{10}H_{14}O$

This contains 10 moles of carbon atom, 14 moles of hydrogen atom and 1 mole of oxygen atom

Now, calculating the mass of carbon in carvone from equation 1, we get:

Molar mass of carbon = 12 g/mol

Moles of carbon = (10 × 0.396) = 3.96 moles

Putting values in equation 1, we get:

$3.96mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=(3.96mol\times 12g/mol)=47.52g$

Hence, the mass of carbon in given amount of carvone is 47.52 grams

6 0

3 years ago

2MG+O2 ...........2MGO

Galina-37 [17]

Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced

5 0

3 years ago

The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume

Viktor [21]

Answer:

0.83 mL

Explanation:

Given data

Initial concentration (C₁): 12 M

Initial volume (V₁): ?

Final concentration (C₂): 1.0 M

Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

7 0

3 years ago

Which one of the following classes of organic compound does not contain the carbonyl (C=O) group?A) aldehydesB) carboxylic acids

vredina [299]

Answer: alcohols

Explanation:

The carbonyl group refers to C=O. It is contained in aldehyde, Ketones, carboxylic acids , esters, amides and acyl chlorides. They are not found in alcohols. The alchols are generally ROH. They do not contain any carbon-oxygen unsaturated bond in their structure hence the answer.

3 0

3 years ago

PLEASE HELP!! A gas has a volume of 7.9 L at a temperature of 222. K and pressure of 877 mmHg. What is the new temperature (in C

Natali5045456 [20]

Answer:

82.97 K

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

Make T' the subject of formula in equation 1

T' = P'V'T/PV................ Equation 2

From the question,

Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L

Substitute these values into equation 2

T' = (0.327×10.41×222.2)/(1.154×7.9)

T' = 82.97 K

Hence the new temperature is 82.97 K

7 0

3 years ago