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Bingel [31]
3 years ago
8

The electron configuration of an element describes _____. Multiple choice question. the relationship between the nucleus of an a

tom and its electrons the types of electronic energy levels that exist within an atom the subatomic particles contained within an atom of the element the distribution of electrons in the orbitals of its atoms
Chemistry
1 answer:
ivolga24 [154]3 years ago
6 0

Answer: the distribution of electrons in the orbitals of its atoms

Explanation:

The electron configuration of an element describes _____. Multiple choice question.

the relationship between the nucleus of an atom and its electrons

the types of electronic energy levels that exist within an atom

the subatomic particles contained within an atom of the element

the distribution of electrons in the orbitals of its atomstal

Element 16 i sulfur

As element 16, it has 16 protons

The neutral atom then also has 16 electrons.

the electrons are b the 1s orbital      2e

                                      2s orbital     2e

                                      2p orbitals   6e

                                      3s orbital     2e

                                      3p orbitals   4e

(note 4 electrons in the 3p orbitals means 4 electrons in the "p" shaped orbitals at the 3rd energy level from the nucleus.

The electronic configuration for sulfur is written as

1s2 2s2 2p6 3s2 3p4

and can be obtained from a proper reading of the periodic table

                       

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A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show
Afina-wow [57]

<u>Answer:</u> The actual yield of the product is 38.57 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of Na = 17.25 g

Molar mass of Na = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of Na}=\frac{17.25g}{23g/mol}=0.75mol

For the given chemical reaction:

2Na+Cl_2\rightarrow 2NaCl

By stoichiometry of the reaction:

2 moles of Na produces 2 moles of NaCl

So, 0.75 moles of Na will produce = \frac{2}{2}\times 0.75=0.75mol of NaCl

We know, molar mass of NaCl = 58.44 g/mol

Putting values in above equation, we get:

\text{Mass of NaCl}=(0.75mol\times 58.44g/mol)=43.83g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(1)

Given values:

Percent yield of the product = 88 %

Theoretical value of the product = 43.83 g

Plugging values in equation 1:

88\% =\frac{\text{Actual yield}}{43.83g}\times 100\\\\\text{Actual yield}=\frac{88\times 43.83}{100}=38.57g

Hence, the actual yield of the product is 38.57 g

3 0
3 years ago
Suppose you increase your walking speed from 7 m/s to 13 m/s in a period of 1 s. what is your acceleration?
GREYUIT [131]
A = change in velocity / time
so change in velocity = 13-7 = 6
so 6/1 =6:
acceleration = 6m/s^2
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2 UO2+ + 4 H+U4+ + UO22+ + 2 H2O is second order in UO2+ and third order overall. Complete the rate law for this reaction in the
mr Goodwill [35]

Answer:

r=k[UO_2^+]^2[H^+]

Explanation:

The given reaction is :-

2UO_2^++4H^+\rightarrow U^{4+}+UO_2^{2+}+2H_2O

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.  

m = 2 =  is order with respect to UO_2^+

n = order with respect to H+

overall order = m+n = 3

n = 3 - m = 3 - 2 = 1

Rate law is:-

r=k[UO_2^+]^2[H^+]

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What is the density of an object if it has a mass of 73 grams and a volume of 3.8cm3?
SashulF [63]

The density of the object is 19 g/cm³.

The mass of the object is 73 g.

The volume of the object is 3.8 cm³.

Density = mass/volume = 73 g/3.8 cm³ = 19 g/cm³

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Answer:

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