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Vlad [161]
3 years ago
9

2 kg and 3 kg objects slide together, and then they break apart. If the final velocity of 2 kg is 10 m/s,

Physics
1 answer:
lara [203]3 years ago
8 0

Answer:

P = (2 + 3) * V       where V is their initial speed  (total momentum)

P = 2 * 10 + 3 * Vx     where Vx here would be V3

If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.

Also work depends on the sum of the velocities

W (initial) = 1/2 (2 + 3) V^2     the initial kinetic energy

W (final) = 1/2 * 2 * V2^2 + 1/2 * 3 * V3^2

It appears that more information is required for this problem

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The total angular momentum of the system about point B is L=m_1r_1\omega_1+m_2r_2\omega_2

Angular momentum, also known as moment of momentum or rotational momentum, is the rotating counterpart of linear momentum.

A rigid object's angular momentum is defined as the product of its moment of inertia and its angular velocity. If there is no external torque on the object, it is analogous to linear momentum and is subject to the fundamental constraints of the conservation of angular momentum principle. The vector quantity angular momentum It is derived from the expression for a particle's angular momentum.

Given,

mass of ball 1 = m1

m₂ mass of ball 2=m2

v₁ is the velocity of ball=r₁ω₁

v₂ is the velocity of ball 2=r₂ω₂

The total angular momentum is given as;

V_{total}=r_1\omega_1+r_2\omega_2\\\\L=m_1r_1\omega_1+m_2r_2\omega_2

Hence the total angular momentum  will be L=m_1r_1\omega_1+m_2r_2\omega_2

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6 0
1 year ago
An oscillator consisting of a material point of m = 200g vibrates under the action of an elastic force according to the equation
Debora [2.8K]

Answer:

an oscillator consisting of a material point of m = 200g vibrates under the action of an elastic force according to the equation y = 0.2sin (π / 4 • t + π / 16) (m)

calculate the period and frequency of the oscillation

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8 0
3 years ago
A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he r
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This question involves the concepts of the law of conservation of energy and kinetic energy.

The girl's fastest speed is "3.7 m/s".

According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:

Loss in Potential Energy = Gain in Kinetic Energy

mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}

where,

v = maximum speed = ?

g = acceleration due to gravity = 9.81 m/s²

Δh = change in height = 1.3 m - 0.6 m = 0.7 m

Therefore,

v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}

<u>v = 3.7 m/s</u>

<u></u>

Learn more about the Law of Conservation of Energy here:

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3 years ago
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