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Vlad [161]
3 years ago
9

2 kg and 3 kg objects slide together, and then they break apart. If the final velocity of 2 kg is 10 m/s,

Physics
1 answer:
lara [203]3 years ago
8 0

Answer:

P = (2 + 3) * V       where V is their initial speed  (total momentum)

P = 2 * 10 + 3 * Vx     where Vx here would be V3

If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.

Also work depends on the sum of the velocities

W (initial) = 1/2 (2 + 3) V^2     the initial kinetic energy

W (final) = 1/2 * 2 * V2^2 + 1/2 * 3 * V3^2

It appears that more information is required for this problem

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A 4.0-kg object moving at 3.0 m/s experiences a 16.0-Newton resistive force over a duration
sveta [45]

Answer:

D is the answer hope you it helps you

7 0
3 years ago
During the day, susan notices that the wind is blowing onshore at the beach. What is this called? land breeze land breeze sea br
In-s [12.5K]

The correct option is (b) Sea breeze

During the day, susan notices that the wind is blowing onshore at the beach called sea breeze.

What is sea breeze?

  • Any wind that flows from a big body of water onto or onto a landmass is called a sea breeze or an onshore breeze.
  • Sea breezes form as a result of changes in air pressure brought on by the different heat capacities of water and dry land. Sea breezes are therefore more confined than prevailing winds.
  • A sea wind is frequently seen along coasts after sunrise because land warms up far more quickly than water does when exposed to solar radiation.
  • The sea wind front is significant because it can serve as a catalyst for afternoon thunderstorms and provide welcome cooling along the coast.

Learn more about the sea breeze with the help of the given link:

brainly.com/question/13015619

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8 0
2 years ago
If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If, instead, you throw it downwar
Korvikt [17]

If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.

To know more about acceleration refer to: brainly.com/question/14468548

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4 0
2 years ago
Squids are the fastest marine invertebrates, using a powerful set of muscles to take in and then eject water in a form of jet pr
tatuchka [14]

Answer:

0.25 m/s

Explanation:

This problem can be solved by using the law of conservation of momentum - the total momentum of the squid-water system must be conserved.

Initially, the squid and the water are at rest, so the total momentum is zero:

p_i = 0

After the squid ejects the water, the total momentum is

p_f = m_s v_s + m_w v_w

where

m_s = 1.60 kg is the mass of the squid

v_s is the velocity of the squid

m_2 = 0.115 kg is the mass of the water

v_w = 3.50 m/s is the velocity of the water

Due to the conservation of momentum,

p_i = p_f

so

0=m_s v_s + m_w v_w

so we can find the final velocity of the squid:

v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.115 kg)(3.50 m/s)}{1.60 kg}=-0.25 m/s

and the negative sign means the direction is opposite to that of the water.

8 0
3 years ago
If heat Q is required to increase the temperature of a metal object from 4 ∘C to 7∘C, the amount of heat necessary to increase i
alisha [4.7K]

Answer:

4Q

Explanation:

Case 1 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 7 - 4 = 3 C

Amount of heat required for the above change of temperature is given as

Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c

Case 2 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 19 - 7 = 12 C

Amount of heat required for the above change of temperature is given as

Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q

Hence the correct choice is

4Q

6 0
3 years ago
Read 2 more answers
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