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Alika [10]
3 years ago
8

A ball is rolling a 5 m/s down a hill the ball has 20 J of energy what is the mass of the ball

Physics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Its 1.6 kg

Remember

E = 1/2mv^2 is the kinetic energy of the ball. The energy is given to you so you need to solve for mass. Rearranging the equation gives you 2E/v^2 = 1.6

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A ventilating fan is operated by 0.5hp electric motor. How much work in joules can the fan do in 3 hours? (I need the answer asa
shtirl [24]

Answer:

Power= 0.5hp = 375W

T = 3hrs = 10800s

Power = Work done/ Time

Work = Power * Time = 375 * 10800 = 4050000J

3 0
3 years ago
the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force bet
kherson [118]

The gravitational force between the objects A. It would increase.

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m_1,m_2 are the masses of the two objects

r is the separation between the objects

In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of m_2 increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.

Therefore, the correct answer is

A. It would increase.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
A 1000 kg car moving at 108 km/h jams on its brakes and comes to a stop. How much work was done by friction?
Nostrana [21]

Answer:

The work done by friction was -4.5\times10^{5}\ J

Explanation:

Given that,

Mass of car = 1000 kg

Initial speed of car =108 km/h =30 m/s

When the car is stop by brakes.

Then, final speed of car will be zero.

We need to calculate the work done by friction

Using formula of work done

W=\Delta KE

W=K.E_{f}-K.E_{i}

W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{f}^2

Put the value of m and v

W=0-\dfrac{1}{2}\times1000\times(30)^2

W=-450000
\ J

W=-4.5\times10^{5}\ J

Hence, The work done by friction was -4.5\times10^{5}\ J

3 0
3 years ago
Help with this question please :>
zheka24 [161]

Answer: A if thats not right its C

Explanation:

3 0
3 years ago
Read 2 more answers
Choose all that apply. Which of the following questions could you answer by measuring length? 1 How tall are you? 2How far is it
horsena [70]

The correct options are:

1 How tall are you?

2How far is it from your house to your school?

3How wide is your refrigerator?

All these measurements involve to measure a length. Instead, the other two options involve to measure different physical quantities; for instance, the question

4 How much does your sister weigh?

Involve to measure a weight (and so, a mass), while the question

5 How warm is it in San Diego?

requires to measure a temperature.

8 0
3 years ago
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