Question

What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere?

Answer 1

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

How to find the weight of a column of air?

• As we know that the expression of pressure as,

                 $P=\frac{F}{A}$

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

• It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

             $P=1atm=1.013*10^5Pascals$

• From this, the value of weight will be,

            $F=mg=P*A=1.013*10^5*4.5=4.56*10^5N$

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

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