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alukav5142 [94]
2 years ago
8

What state of matter is fire?

Chemistry
2 answers:
Y_Kistochka [10]2 years ago
6 0

Answer:

fire is currently considered a plasma.

Explanation:

Fire doesn't fall into liquid, because it doesn't have a fixed volume. Fire doesn't fall into solid, because it doesn't have a fixed shape

Ronch [10]2 years ago
6 0

Answer:

plasma

Explanation:

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A gold coin contains 3.47 × 10^23<br> gold atoms.<br> What is the mass of the coin in grams?
VashaNatasha [74]

Answer:

Mass = 114.26 g

Explanation:

Given data:

Number of gold atoms = 3.47×10²³ atoms

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

3.47×10²³ atoms × 1 mol  /6.022 × 10²³ atoms

0.58 mol

Mass of gold:

Mass = number of moles × molar mass

Mass = 0.58 mol × 197 g/mol

Mass = 114.26 g

4 0
3 years ago
On melting of ice , there is a decrease in volume instead of increase . Why ?
Oliga [24]
Because of the crystal structure of the ice, ice has lower density than liquid water. So the volume of the ice of same mass is greater than water. When melting, the volume will decrease.
8 0
3 years ago
What is the electron configuration of Mn3+
Mumz [18]

Answer:

The electron configuration for a

Mn3+ ion is [Ar]3d4

Explanation:

4 0
3 years ago
The volume of a sample of oxygen is 300.0 mL, when the pressure is 1.00 atm and the temperature is 300K. At what pressure will t
Brut [27]

Answer:

The new pressure is 0.5 atm

Explanation:

Step 1: Data given

Volume of oxygen = 300 mL = 0.300 L

Pressure = 1.00 atm

Temperature = 300 K

The volume increases to 1000mL = 1.00 L

The temperature increases to 500 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 1.00 atm

⇒with V1 = the initial volume = 0.300 L

⇒with T1 = the initial temperature = 300 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 1.00 L

⇒with T2 = the increased temperature = 500 K

(1.00 atm* 0.300 L)/300 K = (P2 * 1.00L) / 500 K

P2 = (1.00 *0.300 * 500) / (300 *1.00)

P2 = 0.5 atm

The new pressure is 0.5 atm

4 0
2 years ago
Please help with any
lys-0071 [83]
10 down: Particle with no charge

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