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3 years ago

Is sulfur dioxide a compound, mixture or element? Thanks!

Chemistry

1 answer:

horsena [70]3 years ago

5 0

It is a compound because a compound is two or more different elements chemically combined.

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Which of the following is not a possible termination step in the free radical chlorination of methane? Group of answer choices ∙

vagabundo [1.1K]

Answer: first option is not a termination

∙CH3 + Cl2 → CH3Cl + Cl∙

Explanation:

Since a radical is formed as part of the product it means it's a propagation step and not a termination step, at termination no free radical exist as product

7 0

3 years ago

Paleontologists have discovered several ancestors of the modern horse.

ExtremeBDS [4]

Answer:

hyracotherium

Explanation:

..........

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3 years ago

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Could an organism survive without its mitochondria if all the other organelle were present

lisov135 [29]

No, <span>mitochondria convert the sugar, can give it(the cell) Nutrients (food) to mainly keep it fresh and alive. Without cells mitochondria can't do its job.</span>

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4 years ago

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Which element below is the most reactive? Hydrogen chlorine neon oxygen

trapecia [35]

Answer:

Chlorine

Explanation:

Chlorine has an atomic number of 17 and a configuration of 2, 8, 7. In the outermost shell, it has 7 seven electrons which means that it needs just one more electron to attain an octet configuration in that shell. Therefore it's can react quickly with any nearby nucleophile.

5 0

3 years ago

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One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

3 years ago