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snow_lady [41]
3 years ago
15

Is sulfur dioxide a compound, mixture or element? Thanks!

Chemistry
1 answer:
horsena [70]3 years ago
5 0
It is a compound because a compound is two or more different elements chemically combined.
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Helppp please pleaseeee
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D

Explanation:

The answer will be D because as we can deduct from the hypothesis, he will try to control the amount of food he gives the rats in order to see if in fact the fue of the mouse will be shinier

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36 g of water vapor takes up how many liters at room temperature and pressure of 293K and 100 K PA
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100kpa is correct .100 kpa is correct

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What particle is needed to complete the following equation 14 7 n + 14 6 c +1 1 h
Rama09 [41]
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6 0
4 years ago
Given an initial cyclopropane concentration of 0.00560 m, calculate the concentration of cyclopropane that remains after 1.50 ho
maria [59]

<span>We can solve this problem by assuming that the decay of cyclopropane follows a 1st order rate of reaction. So that the equation for decay follows the expression:</span>

A = Ao e^(- k t) 

Where,

A = amount remaining at time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560 M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>

The rate constant should be given in the problem which I think you forgot to include. For the sake of calculation, I will assume a rate constant which I found in other sources:

k = 5.29× 10^–4 s–1                     (plug in the correct k value)

<span>Plugging in the values in the 1st equation:</span>

A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )

A = 3.218 <span>× 10^–4 M           (simplify as necessary)</span>

8 0
3 years ago
[Co(H2O)6]2+(aq) + 4Cl-(aq) ⇌ [CoCl4]2-(aq) + 6H2O(l)
pav-90 [236]

<u>Answer:</u>

<u>For A:</u> The expression for K_{eq} is given below.

<u>For B:</u> The value of K_{eq} at 25°C is 0.0185512

<u>For C:</u> The value of K_{eq} at 65°C is 0.2887886

<u>For D:</u> The reaction is endothermic in nature.

<u>Explanation:</u>

  • <u>For A:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For the given chemical reaction:

[Co(H_2O)_6]^{2+}(aq.)+4Cl^-(aq.)\rightleftharpoons [CoCl_4]^{2-}(aq.)+6H_2O(l)

The expression of K_{eq} for above equation without the concentration of liquid water is:

K_{eq}=\frac{[CoCl_4]^{2-}}{[Co(H_2O)_6]^{2+}[Cl^-]^4}      ......(1)

The expression is written above.

  • <u>For B:</u>

We are given:

[CoCl_4]^{2-}=0.0334612M

[Co(H_2O)_6]^{2+}=0.966539M

[Cl^-]=1.86616M

Putting values in equation 1, we get:

K_{eq}=\frac{0.0334612}{0.966539\times 1.86616}=0.0185512

Hence, the value of K_{eq} at 25°C is 0.0185512

  • <u>For C:</u>

We are given:

[CoCl_4]^{2-}=0.234625M

[Co(H_2O)_6]^{2+}=0.765375M

[Cl^-]=1.06150M

Putting values in equation 1, we get:

K_{eq}=\frac{0.234625}{0.765375\times 1.06150}=0.2887886

Hence, the value of K_{eq} at 65°C is 0.2887886

  • <u>For D:</u>

For Endothermic reactions, \Delta H>0, which is positive

For Exothermic reactions, \Delta H, which is negative

To calculate \Delta H of the reaction, we use Van't Hoff's equation, which is:

\ln(\frac{K_{65^oC}}{K_{25^oC}})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{65^oC} = equilibrium constant at 65°C = 0.2887886

K_{25^oC} = equilibrium constant at 25°C = 0.0185512

\Delta H = Enthalpy change of the reaction = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 25^oC=[25+2730]K=298K

T_2 = final temperature = 65^oC=[65+2730]K=338K

Putting values in above equation, we get:

\ln(\frac{0.2887886}{0.0185512})=\frac{\Delta H}{8.314J/mol.K}[\frac{1}{298}-\frac{1}{338}]\\\\\Delta H=57471.26J/mol

As, the calculated value of \Delta H>0. Thus, the reaction is endothermic in nature.

4 0
3 years ago
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