Answer:
The correct answer is "
". A further explanation is given below.
Explanation:
- Throughout all the three instances (worst, average as well as best), the time complexity including its Merge sort seems to be
as the merge form often splits the array into two halves together tends to linear time to combine multiple halves. - As an unsorted array, it needs an equivalent amount of unnecessary capacity. Therefore, large unsorted arrays are not appropriate for having to search.
Answer:


The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.

Explanation:
The peak voltage after the 6 to 1 step down is
. Then, the peak voltage of the rectified output is
V_{d}[/tex] and according to the statement, the diodes can be modeled to be
. Then, the peak voltage in the load is
.
The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.
The average output voltage is calculated as:

The average current in the load is calculated as:

Answer:
Both A and B are correct.
Explanation:
The crankshaft sensor is attached to the crankshaft pulley on the
back side of the crankshaft. It is used to pass a signal to the PCM
which controls the ignition of an engine. This sensor helps in providing some basic timing for the signal. If there is a faulty sensor present, the signal will not be received by the PCM. So, it will affect the engine while starting. One reason can be a defective
assembly of the coil.
If there is a faulty
, the signal will not be received properly. This will not allow the passing of signals to the ignition system. This will cause a misfire. One of the most common causes of
misfire is a faulty ignition coil. This will affect the working of a
sensor. So, prevent engine from starting.
Answer:
Increase the eletric current
slow down the resistance
Explanation: