How to measure the quality of the output signal in ADC?
1 answer:
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Answer:
C
Explanation:
N = Na.P/A------(1)
Na = avogadro's number = 6.02210²³
P = density
A = atomic weight of metal
When we substitute into equation 1 above we get
1.0x10²⁹atoms/m³
From here we calculate the number of vacancies
T = 1000⁰c = 1273K
The formula to use is
Nv= Nexo(Qt/K.T) -----(2)
Qt = 1.22eV
K = Boltzmann's constant = 8.6210x10^-5
When we substitute values into equation 2
We get Nv = 1.49 x 10²⁴m-3
Therefore option c is correct
Check attachment for a more detailed calculation of this question
Answer:
the three part are mass, spring, damping
Explanation:
vibrating system consist of three elementary system namely
1) Mass - it is a rigid body due to which system experience vibration and kinetic energy due to vibration is directly proportional to velocity of the body.
2) Spring - the part that has elasticity and help to hold mass
3) Damping - this part considered to have zero mass and zero elasticity.
Answer:
The velocity at section is approximately 42.2 m/s
Explanation:
For the water flowing through the pipe, we have;
The pressure at section (1), P₁ = 300 kPa
The pressure at section (2), P₂ = 100 kPa
The diameter at section (1), D₁ = 0.1 m
The height of section (1) above section (2), D₂ = 50 m
The velocity at section (1), v₁ = 20 m/s
Let 'v₂' represent the velocity at section (2)
According to Bernoulli's equation, we have;
Where;
ρ = The density of water = 997 kg/m³
g = The acceleration due to gravity = 9.8 m/s²
z₁ = 50 m
z₂ = The reference = 0 m
By plugging in the values, we have;
50 m + 30.704358 m + 20.4081633 m = 10.234786 m +
50 m + 30.704358 m + 20.4081633 m - 10.234786 m =
90.8777353 m =
v₂² = 2 × 9.8 m/s² × 90.8777353 m
v₂² = 1,781.20361 m²/s²
v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s
The velocity at section (2), v₂ ≈ 42.2 m/s
Answer:
attached below
Explanation:
