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kherson [118]
3 years ago
13

3.) What would 9 gallons of gas cost at $2.12 per gallon? *

Mathematics
1 answer:
kirill115 [55]3 years ago
5 0

Answer:

19.08

Step-by-step explanation:

each gal = $2.12

gals filled = 9

9 x 2.12 = 19.08

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Marion Lamar establish a tutoring service at a local mall they tutor college students in math and English they charge $40 per ho
Readme [11.4K]

Answer: $3300 profit

Step-by-step explanation

P = 40(h) - expenses

h = 200

Expenses = 4000,325,375

P = 40(200) - (4000+325+375)

P = 8000 - 4700

P = 3300

4 0
3 years ago
Which pair of angles are vertical angles? ∠KRC and ∠CRH ∠MRC and ∠KRM ∠ERT and ∠MRC ∠KRE and ∠ERT Lines K H, M T, and E C inters
hram777 [196]
The best and the most correct answer among the choices provided by the question is the first choice. The pair of angles that are vertical is <span>∠KRC and ∠CRH ∠MRC and ∠KRM ∠ERT. </span>I hope my answer has come to your help. God bless and have a nice day ahead!
8 0
3 years ago
Whoever gets this right gets brainliest!
Ainat [17]
The slope of function A is 6 more than function B this is because y = 9x + 4 for a function this form the slope is the x - coefficient or in this case 9 and since we already now that the functions slope is 3 subtract 3 from 9 to get the answer 6.
7 0
3 years ago
Rationalize the denominator.
Maslowich
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166412

——————————
 
     \mathsf{\dfrac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}}


Multiply and divide by the conjugate of the denominator, which is \mathsf{\sqrt{a}+2\sqrt{y}:}

     \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}\\\\\\ \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)^2}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}

The numerator is a square of a sum, and the denominator is the product of a difference and a sum (product of two conjugates). Then, expand the common products:
 
     \mathsf{=\dfrac{\big(\sqrt{a}\big)^2+2\cdot \sqrt{a}\cdot 2\sqrt{y}+\big(2\sqrt{y}\big)^2}{\big(\sqrt{a}\big)^2-\big(2\sqrt{y}\big)^2}}\\\\\\ \mathsf{=\dfrac{a+4\cdot \sqrt{a}\cdot \sqrt{y}+2^2\cdot \big(\sqrt{y}\big)^2}{a-2^2\cdot \big(\sqrt{y}\big)^2}} 

     \mathsf{=\dfrac{a+4\sqrt{ay}+4y}{a-4y}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

8 0
3 years ago
Lesson 1-5. Name the angle(s) in the diagram described by each of the following. Plz help​
denis-greek [22]

Answer:

n

Step-by-step explanation:

6 0
3 years ago
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