Answer:
(2 x 10) + (4 x 1) + (2 x 0.1) + (1 x 0.01)
Step-by-step explanation:
Answer:
(hopefully) 2,600
Explanation:
5350 mm = 535 cm
= 535 x 5( 5 ropes) = 2675 cm
= 15 cm × 5 ( five knots for 5 ropes) = 75cm
= 2675- 75 = 2600.
hopefully im right...
Answer:
b
Step-by-step explanation:
Give me brain list plssssss
Answer:
The value is ![P(| \^ p - p| < 0.05 ) = 0.9822](https://tex.z-dn.net/?f=P%28%7C%20%5C%5E%20p%20-%20%20p%7C%20%3C%200.05%20%29%20%3D%200.9822%20)
Step-by-step explanation:
From the question we are told that
The population proportion is ![p = 0.52](https://tex.z-dn.net/?f=p%20%3D%20%200.52)
The sample size is n = 563
Generally the population mean of the sampling distribution is mathematically represented as
![\mu_{x} = p = 0.52](https://tex.z-dn.net/?f=%5Cmu_%7Bx%7D%20%3D%20%20p%20%3D%20%200.52)
Generally the standard deviation of the sampling distribution is mathematically evaluated as
![\sigma = \sqrt{\frac{ p(1- p)}{n} }](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%20%5Csqrt%7B%5Cfrac%7B%20p%281-%20p%29%7D%7Bn%7D%20%7D)
=>
=>
Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as
![P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))](https://tex.z-dn.net/?f=P%28%7C%20%5C%5E%20p%20-%20%20p%7C%20%3C%200.05%20%29%20%3D%20%20P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29)
Here
is the sample proportion of persons with a college degree.
So
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%28%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D-%200.52%7D%7B0.02106%7D%20%3C%20%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3C%20%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D%20%2B%200.52%7D%7B0.02106%7D%20%29)
Here
![\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3D%20Z%20%28The%5C%20standardized%20%5C%20%20value%20%5C%20%20of%5C%20%20%28%5C%5E%20p%20-%20p%29%29)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%5Cfrac%7B-0.47%20-%200.52%7D%7B0.02106%20%7D%20%20%3C%20%20Z%20%20%3C%20%5Cfrac%7B-0.47%20%2B%200.52%7D%7B0.02106%20%7D%5D)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%20-2.37%20%3C%20%20Z%20%20%3C%202.37%20%5D)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%28Z%20%3C%20%202.37%20%29%20-%20P%28Z%20%3C%20-2.37%20%29)
From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is
![P(Z < 2.37 ) = 0.9911](https://tex.z-dn.net/?f=P%28Z%20%3C%20%202.37%20%29%20%3D%200.9911)
and
![P(Z < - 2.37 ) = 0.0089](https://tex.z-dn.net/?f=P%28Z%20%3C%20%20-%202.37%20%29%20%3D%200.0089)
So
=>
=>
=> ![P(| \^ p - p| < 0.05 ) = 0.9822](https://tex.z-dn.net/?f=P%28%7C%20%5C%5E%20p%20-%20%20p%7C%20%3C%200.05%20%29%20%3D%200.9822%20)
Amma solve it first then ill tell you what i got as the answer:)