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Mars2501 [29]
2 years ago
6

⟟ need help with this please someone and please don’t do links

Mathematics
1 answer:
ANEK [815]2 years ago
8 0
B B B B B B B B B B B
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Question 12 (5 points)
NemiM [27]

Answer:

D) If WX = XY and XY = YZ, then WX = YZ.

Step-by-step explanation:

The transitive property states that if a=b and b=c, then a=c. So, if two different values equal to the same, separate value, then they are also congruent. The answer choice, d, represents this idea because WX and YZ both equal XY and are shown to be equal.

6 0
3 years ago
(picture included) will mark brainliest
Anarel [89]

Answer:

1. A

2. C

3. B

Step-by-step explanation:

1. we can create an equation y = 48x + 96

if we plug in 1 we get 144

2. we can create an equation y = 10x to represent how much battery you will lose every hour

if we plug in 5 to x, we get y = 50

so we get the plot point: (5, 50)

3. process of elimination

5 0
3 years ago
For every 1 litre of water used to make a
Komok [63]

Step-by-step explanation:

hope you can understand

7 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2
kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed a\leq x \leq b and in your case \nexists x\in\mathbb{Z}: a\leq x\leq b for a>b

In fact, considering a set S we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing $ that satisfy S = S \cup \varnothing

This means that, by definition \sum_{x=a}^b \varnothing = 0

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

we have other problems. Actually, this case is really bad.

Note that \cos^2(\infty) has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$, the cosine function oscillates between [-1, 1] , and therefore it is undefined. Thus, we cannot evaluate

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0
3 years ago
Given:
lys-0071 [83]

Answer:

PS=13\text{ units}

Step-by-step explanation:

So, we know that PR is 20, SR is 11, and QS is 5.

We also know that PQ is perpendicular to QR, forming the right angle at ∠Q.

We know all the side lengths except for PQ and PS (the one we want to find). Notice that if we find PQ first, we can then use the Pythagorean Theorem to find PS since we already know QS.

So, let's find PQ.

We can see that we can also use the Pythagorean Theorem on PQ. PQ, QR, and PR (the hypotenuse) will be our sides. So:

(PQ)^2+(QR)^2=(PR)^2

We know that PR is 20.

QR is the combined length of QS+SR, so QR is 5+11 or 16.

So, substitute:

(PQ)^2+(16)^2=(20)^2

Solve for PQ. Square:

(PQ)^2+256=400

Subtract 256 from both sides:

(PQ)^2=144

Take the square root of both sides:

PQ=12

So, the side length of PQ is 12.

Now, we can use the Pythagorean Theorem again to find PS. Notice that PQ, QS, and PS also form a right triangle, with PS being the hypotenuse. So:

(PQ)^2+(QS)^2=(PS)^2

We already know that QS is 5. We also just determined that PQ is 12. Substitute:

(12)^2+(5)^2=(PS)^2

Square:

144+25=(PS)^2

Add:

169=(PS)^2

Take the square root of both sides:

PS=13

Therefore, the length of PS is 13 units.

And we're done!

7 0
3 years ago
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