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Temka [501]
2 years ago
6

Describe how to solve an exponential equation with unlike bases.

Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
7 0

Answer:

How do you calculate exponents with different bases?

Image result for how to solve an exponential equation with unlike bases.

When multiplying exponents with different bases and the same powers, the bases are multiplied first. This can be written mathematically as an × bn = (a × b)n. When the exponents with different bases and different powers are multiplied, each exponent is evaluated separately and then multiplied.

hope it helped it !!

kari74 [83]2 years ago
4 0

Answer:

Mark me as brainlist

Step-by-step explanation:

Use logarithms to solve exponential equations whose terms cannot be rewritten with the same base

Solve exponential equations of the form    

y

=

A

e

k

t

 for t

Recognize when there may be extraneous solutions or no solutions for exponential equations

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4 0
3 years ago
Add.3/2a+5/2a PLease help!
Wittaler [7]
The answer should be 4a

4 0
3 years ago
Read 2 more answers
5. How many solutions does the equation<br> 7x + 3x – 8= 2(5x – 4) have? Explain.
GREYUIT [131]

Answer:

Your answer is: Infinitely Many

Any value of  x  makes the equation true.  Also, they are all real numbers.

Step-by-step explanation:

If you are solving to find all Complex Number Solutions: ↓

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6 0
3 years ago
A^2-b^2 a^2b-ab^2<br>-------------- ÷ ---------------a^2b+ab^2 a^2b- ab^2​
Damm [24]

Answer:

\huge{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}

Step-by-step explanation:

\huge{ \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b}  +  {ab}^{2}  }  \div  \frac{ {a}^{2b} -  {ab}^{2}  }{ {a}^{2b} -  {ab}^{2}  }}

\huge{\frac{ {x}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }  \div 1}

\huge{\boxed{\green{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}}}

5 0
3 years ago
Reflection across y = -x please I need help I will mark you brainless
tresset_1 [31]
Answer is
U= (-2,2)
V=(-2,4)
W= (-4,3)

Step by step
Find points for the triangle.
Using the rule for reflection across y axis.

The rule for a reflection over the y -axis is (x,y)→(−x,y)

U (2,2) ➡️ (-2,2)

V (2,4) ➡️ (-2,4)

W (4,3) ➡️ (-4,3)

4 0
1 year ago
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