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zheka24 [161]
3 years ago
13

What is the purpose of the red-core yarns in the synthetic sling?

Engineering
1 answer:
Leona [35]3 years ago
5 0

An immediate strength loss. This is why Sling Webbing has red core yarns to visually reveal damage and act as a basis for sling rejection.

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Hi all, could you solve this please?<br> What is the value of the resistance R
Kazeer [188]

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try to 36v power and take 1a and intersect to 3

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What type of footwear protects your toes from falling objects and being crushed?
Lady bird [3.3K]

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6 0
4 years ago
Read 2 more answers
The consumer price index (CPI) for a given year is the amount of money in that year that has the same purchasing power as $100 i
Kipish [7]

Answer:

The formula should be 234.1 x (1 + 2.9%)^t

Explanation:

As the questions indicates, the CPI indicates what the value for money is in that given year compared to the base year. So a higher CPI amount is given as a result of inflation over the years. So the rate of inflation was such that the 100 dollars in 1983 (taken as the base year) is equivalent to 234.1 in 2015 as a result of inflation. So, essentially, the time value of money concept is being applied here. We can use the formula for calculating the future value of money over here as well.

The equation is: FV = PV × (1 + x%)^t

where, FV is future value, PV is the present value today, x% is the rate of change, and t is the time period in years.

With the values at hand, the formula to compute what the CPI should be t years after 2015,

CPI (t years after 2015) = 234.1 x (1.029)^t

3 0
3 years ago
Purely resistive loads of 24kW, 18kW and 12kW are connected between the neutral and the red, yellow and the blue respectively of
seraphim [82]

Answer:

The phase current in each line conductor are;

I_{R} = 100.17 < 0A

I_{Y} = 75.13< - 120A

I_{B} = 50.08

Explanation:

Given the following data;

Red phase = 24kW,

Yellow phase = 18kW

Blue phase = 12kW

Line voltage = 415V

For a star connected system, we have;

Phase voltage (V_{p} ) = \frac{Line voltage}{\sqrt{3}}

Phase voltage (V_{p} ) = \frac{415}{\sqrt{3}}

Phase voltage (V_{p} ) = 239.6V

The phase sequence for RYB is given by;

V_{R} = 239.6

Phase current (I) = \frac{Phase power}{Phase voltage}

Hence, I = \frac{P}{V}

<em>For the Red phase;</em>

I_{R} = \frac{24000}{239.6

I_{R} = 100.17 < 0A

<em>For the Yellow phase;</em>

I_{Y} = \frac{18000}{239.6

I_{Y} = 75.13< - 120A

<em>For the Blue phase;</em>

I_{B} = \frac{12000}{239.6

I_{B} = 50.08

For the line neutral;

I_{N} =\sqrt{ (I_{R}^{2} +I_{Y}^{2}+I_{B}^{2}-I_{R}I_{Y}-I_{Y}I_{B}-I_{R}I_{B}

Substituting we have, I_{N} = 43.29A

6 0
3 years ago
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