Ok there........................................................................

C&A's potato chip filling process has a lower specification limit of 9.5 oz. and an upper specification limit of 10.5 oz. Th

Law Incorporation [45]

Answer:

Process capability index = (USL - LSL)/6Sigma = 1/6(0.3)= 0.56

Answer (a) 0.56

Explanation:

3 0

4 years ago

A fuel gas containing 45.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00 degree C, and th

Dennis_Churaev [7]

Answer:

A)

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor = -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate - Q ( KJ )

- Q ( kj ) for vapor = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

since combustion takes place in a constant-volume batch reactor

7 0

3 years ago

A 1m3 tank containing air at 25℃ and 500kPa is connected through a valve to

Aliun [14]

Answer:

The right answer is "2.2099 m³".

Explanation:

Given:

Mass,

m = 5 kg

Temperature,

T = 35℃

or,

= 35 + 273

Pressure,

P = 200 kPa

Gas constant,

R = 0.2870 kj/kgK

By using the ideal gas equation,

The volume will be:

⇒ $PV=mRT$

or,

⇒ $V=\frac{mRT}{P}$

By substituting the values, we get

$=\frac{5(0.2870)(35+273)}{200}$

$=\frac{441.98}{200}$

$=2.2099 \ m^3$

8 0

3 years ago

What is pixel's intensity ?

bonufazy [111]

Answer:

Small points of colored light arranged in a grid, each is formed from three colored lights: red,green,and blue. (RGB), nothing is absorbed,nothing is reflected, just see pure colored lights.

7 0

4 years ago

Water is flowing in a metal pipe. The pipe OD (outside diameter) is 61 cm. The pipe length is 120 m. The pipe wall thickness is

Yuki888 [10]

Answer:

1113kN

Explanation:

The ouside diameter OD of the pipe is 61cm and the thickness T is 0.9cm, so the inside diameter ID will be:

Inside Diameter = Outside Diameter - Thickness

Inside Diameter = 61cm - 0.9cm = 60.1cm

Converting this diameter to meters, we have:

$60.1cm*\frac{1m}{100cm}=0.601m$

This inside diameter is useful to calculate the volume V of water inside the pipe, that is the volume of a cylinder:

$V_{water}=\pi r^{2}h$

$V_{water}=\pi (\frac{0.601m}{2})^{2}*120m$

$V_{water}=113.28m^{3}$

The problem gives you the water density d as 1.0kg/L, but we need to convert it to proper units, so:

$d_{water}=1.0\frac{Kg}{L}*\frac{1L}{1000cm^{3}}*(\frac{100cm}{1m})^{3}$

$d_{water}=1000\frac{Kg}{m^{3}}$

Now, water density is given by the equation $d=\frac{m}{V}$ , where m is the water mass and V is the water volume. Solving the equation for water mass and replacing the values we have: