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3 years ago

How do you take a picture

2 answers:

7 0

to take a picture just choose “take photo” on the button next to the keypad, if you are on a computer it’s the same thing if your computer has a video screener or whatever they call it but if not I’m not sure, hope this helps!

svet-max [94.6K]3 years ago

3 0

Answer:

Explanation:

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If i eat myself will I get twice as big or disappear completely?

Butoxors [25]

Disappear completely

5 0

3 years ago

I want to cancel my membership

Dennis_Churaev [7]

1. Go to settings 2. Press on your Apple ID 3. Press on subscriptions then turn them off.

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2 years ago

Which of the following uses pressure and flow to transmit power from one location to another?

lord [1]

Answer:

fluid power

Explanation:

fluids commonly used in fluid power are Oil, Water, Air, CO², and Nitrogen gas, fluid power is commonly confused with hydraulic power, which only uses liquids, fluid power uses either liquids or gases

5 0

2 years ago

A microwave transmitter has an output of 0.1W at 2 GHz. Assume that this transmitter is used in a microwave communication system

Len [333]

Answer:

gain = 353.3616

P_r = 1.742*10^-8 W

Explanation:

Given:

- The output Power P_o = 0.1 W

- The diameter of the antennas d = 1.2 m

- The frequency of signal f = 2 GHz

Find:

a. What is the gain of each antenna?

b. If the receiving antenna is located 24 km from the transmitting antenna over a free space path, find the available signal power out of the receiving antenna.

Solution:

- The gain of the parabolic antenna is given by the following formula:

gain = 0.56 * 4 * pi^2 * r^2 / λ^2

Where, λ : The wavelength of signal

r: Radius of antenna = d / 2 = 1.2 / 2 = 0.6 m

- The wavelength can be determined by:

λ = c / f

λ = (3*10^8) / (2*10^9)

λ = 0.15 m

- Plug in the values in the gain formula:

gain = 0.56 * 4 * pi^2 * 0.6^2 / 0.15^2

gain = 353.3616

- The available signal power out from the receiving antenna is:

P_r = (gain^2 * λ^2 * W) / (16*pi^2 * 10^2 * 10^6)

P_r = (353.36^2 * 0.15^2 * 0.1) / (16*pi^2 * 10^2 * 10^6)

P_r = 1.742*10^-8 W

4 0

3 years ago

Determine the mass density of an oil if 0.3 tonnes of the oil occupies a volume of 4m.

Yuki888 [10]

Answer:

Do you mean 4m^3 and 3.0 tones?

Explanation:

solution:

Mass = m = 3.0 tones

- 1 ton = 1,000 kg

= 3.0 × 1,000

= 3,000 kg

volume = v = 4m^3

Required:

Mass density of oil = p = ?

We know that;

$p = \frac{mass}{volume} = \frac{m}{v} = \frac{3000}{4} = 750kg |m^{3} ans$

The answer is:

750kg / m^3

8 0

3 years ago